Answer:
2.475 mol of O2 formed.
Explanation:
Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.
x mole of O2 = 1.65 mol KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2
x mole of O2 formed = 2.475 mol of O2
Answer:
52.2g of KCl would be left
The mass of KCl will remain despite the solution is been heated
Explanation:
When you are heating a solution, just the solvent (In this case, water), will be evaporated and, in theory, the mass of KCl will remain despite the solution is been heated.
Now, the mass of KCl that you can obtain from 350mL of a 2.0M solution will be:
<em>Moles KCl:</em>
350mL = 0.350L * (2.0mol / L) = 0.700 moles
<em>Mass KCl -Molar mass: 74.55g/mol-:</em>
0.700mol * (74.55g/mol) = 52.2g of KCl would be left
Cs is the answer hope this helps!!!
Answer:
r² x h
Explanation:
A can is cylindrical in nature. Using the formula of the volume of the can, we can find this unknown volume.
The volume of cylinder is given as:
Volume of a cylinder = Area x height
Volume of a cylinder = r² x h
Therefore density of the can;
Density = 
