Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z = 
~ N(0,1)
where, 
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P( > 
) = P(Z > 1.25) = 1 - P(Z 
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Given the graph, you can assume that f(x) is the y of an equation.
When f(2) is given, this means that what is the y value when x=2?
As you can see, the solution is between 8 and 10. Meaning that the closest answer is 9.
Hope I helped :)
Answer:
36 × 18=648
Step-by-step explanation:
first one should do the area which results to 36 inches.
secondly do 3 × length of each side of the rectangle since scale factor is gotten by doing the recipricol of the scale factor given.
Answer:
(x, y) ⟶ (x + 4, y + 2)
Step-by-step explanation:
If you shift a point four units to the right, x ⟶ x + 4.
If you shift it up two units, y ⟶ y + 2.
If you combine the two shifts into one transformation, the rule becomes
(x, y) ⟶ (x + 4, y + 2)
Answer:
27 blue squares
Step-by-step explanation:
36÷4=9. 9×3=27
