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1 year ago

WILL MARK BRAINLIEST PLEASE HELP thanksss

Mathematics

1 answer:

Alenkasestr [34]1 year ago

4 0

The image of rectangle JKLM after a reflection over the y-axis around the origin is J = (6, -2), K = (6, -1), L = (0, -1) and M = (0, -2)

<h3>How to graph the image of rectangle JKLM after a reflection over the y-axis around the origin?</h3>

From the graph, the coordinates of the rectangle are:

J = (-6, -2)

K = (-6, -1)

L = (0, -1)

M = (0, -2)

The rule of a reflection over the y-axis around the origin is

(x, y) = (-x, y)

When the above rule is applied, we have the image to be:

J = (6, -2)

K = (6, -1)

L = (0, -1)

M = (0, -2)

Hence, the image of rectangle JKLM after a reflection over the y-axis around the origin is J = (6, -2), K = (6, -1), L = (0, -1) and M = (0, -2)

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If BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6, what are the values of x and AC?

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Answer: x=7 and AC = 44 unuts.

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other. (i)

Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.

BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6

Using (i)

$BE=\dfrac{BD}{2}\\\\2x+2=\dfrac{5x-3}{2}\\\\ 2(2x+2)=5x-3\\\\ 4x+4= 5x-3\\\\ 5x-4x=4+3\\\\ x= 7$

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AC =2 AE = 2 (22) =44 units.

Hence, x=7 and AC = 44 unuts.

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