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Cloud [144]
3 years ago
8

Three of the thirty computers are out of service. What percent of the computers are working?

Mathematics
2 answers:
kherson [118]3 years ago
8 0

Answer: 66.6 oercent

Step-by-step explanation: Hope this helps

Vera_Pavlovna [14]3 years ago
7 0

Answer:

90% percent of the computers are working.

Step-by-step explanation:

3/30 of the computers don't work and we can simplify this

1/10 or 10% Subtract 10% from 100%

90% are working computers.

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kolezko [41]

This might be wrong but I got .024806509

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What is 1+12x-40 evaluated
vlada-n [284]

Answer:

12x-39

Step-by-step explanation:

40-1=39

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Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
2 years ago
What is the GCF for each set of numbers 9 and 27
galben [10]
The greatest common factor 9 and 27 is 9.

The factors of 9 are 9, 3, 1. The factors of 27 are 27, 9, 3,
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Svetach [21]
W^B = W×W×W×W... (#B times)
Something along those lines.
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