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Vaselesa [24]
2 years ago
11

An unknown nucleus has twice the volume of a nucleus with 73 nucleons. what is the atomic mass number of the unknown nucleus?

Chemistry
1 answer:
lyudmila [28]2 years ago
6 0

The atomic mass number of the unknown nucleus is 128.

The relationship between the radius of the nucleus r and the atomic mass A is given by

r ≈ (1.2  X 10^{-15}m )A^{\frac{1}{3} }

If we assume that the nucleus is a sphere, the volume V is

V = \frac{4}{3}\pi r^{3}

let the volume of the nucleus having atomic mass number of 64 be V, then the volume of the unknown nucleus having atomic mass number A is written as

=2 X \frac{4}{3} \pi (1.2 X 10^{-15})^{3} X 64\\\\=\frac{4}{3} \pi (1.2 X 10^{-15})^{3} X A

Thus, we find that the atomic mass number of the unknown nucleus is A=128

Learn more about atomic mass nuclear charge:

brainly.com/question/13537766

#SPJ4

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Which of the procedures, if either, is more accurate when making a 1/501/50 dilution of a solution? Transfer 1 mL1 mL with a pip
nikitadnepr [17]

Full question:

First of all, bear in mind that this question is incomplete. Here is the full question:

  • Which of the procedures, if either, is more accurate when making a 1/50 dilution of a solution?

a) Transfer 1 mL with a pipet into a 50-mL volumetric flask.

b) Transfer 20 mL with a pipet into a 1-L volumetric flask.

c) Both procedures have the same accuracy.

  • How can the accuracy of either procedure be improved?

a) Use an Erlenmeyer flask instead of a volumetric flask.

b) Use a graduated cylinder instead of a pipet for the transfer.

c) Calibrate each piece of glassware.

d) Instead of using a 1/50 dilution to make the solution, weigh out the material on a balance and transfer ir directly to the volumetric flask.

Answer:

1) c) Both procedures have the same accuracy.

2) c) Calibrate each piece of glassware.

Explanation:

1) Given that the 1/50 relation is maintained whether we pour 1 mL into a 50-mL volumetric flask or we transfer 20 mL with a pipet into a 1-L volumetric flask, both procedures have the same accuracy (because in both procedures we are using volumetric glassware).

When we want the most exact result possible, we need to calibrate the volumetric glassware used (bear in mind that the only volumetric glassware is the buret, the volumetric flask, the micropipet and the pipet). This is usually done measuring the mass of water poured by the recipient or contained in it, and using the density of that liquid to convert mass into volume. In this way is possible, for example, to determine that a pipet poured 10.016 mL and not 10.000 mL.

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Name the following molecules:
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Why would a C-O bond have only provide 358 kJ/mol each while C=O provides 799 kJ/mol? Explain in detail.
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Consider the amount of energy needed to brake the bonds.

In c=o there are both a pi-bond and a sigma bond. Therefore it requires a higher energy to brake it. When considering the c-o bond there is only a single sigma bond is needed to be broken. Therefore braking is easier.

When something is easily broken they are having a weak attraction. When they harder to break they are having a stronger attraction.

Here weak attraction is having a lower energy while stronger attraction has higher energy.

Therefore c=o provides a high energy than c-o

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3 years ago
What descriptive term is applied to the type of diene represented by 2,4-hexadiene?.
Varvara68 [4.7K]

The descriptive term applied to the type of diene represented by 2,4-hexadiene is conjugated diene.

Dienes are compounds which contains two double bonds. These dienes can be non conjugated or conjugated.

Conjugated diene are those compound which have two double bonds  joined by a single σ bond. Conjugated dienes can also be called 1,3-diene. To know if diene is conjugated or non conjugated, sp³ hybridization is to b checked and the number of double bonds and single sigma bond is checked.

Conjugated dienes are found in many different molecules. 2,4-hexadiene is a conjugated diene with two carbon-carbon double bonds that are separated by one sigma bond.

The stabilization of dienes by conjugation is better than the aromatic stabilization. Conjugated dienes are more stable than non conjugated or cumulative diene because it has higher electron density of molecules delocalized.

To learn more about conjugated dienes,

brainly.com/question/24261651

#SPJ4

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