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Lilit [14]
2 years ago
8

Practice question 1 How many moles are in 5.64e25 atoms of iron (Fe)?​

Chemistry
1 answer:
liberstina [14]2 years ago
6 0

1 mole is equal to 6.0220 x 1023 atoms of any element.

You might be interested in
Which of the five most abundant elements are metals?
Gala2k [10]

Answer:

Oxygen

Silicon

Aluminium

Iron

Calcium

Explanation:

Oxygen=47 percent

Silicon=28 percent

Aluminium=8 percent

Iron=5 percent

Calcium=3.5 percent

Hope it helps :)

Mark me as brainliest

6 0
3 years ago
Compute the percent ionic character of the interatomic bonds for the following compounds : a. TiO2 b. ZnTe c. CsCld. InSb e. MgC
sesenic [268]

Answer:

a. 63.2%

b. 11.7%

c. 73.3%

d. 0.995%

e. 55.5%

Explanation:

An ionic compound is a compound that is formed by ions, so one of the elements must donate electrons (which is the cation, the positive ion), and the other will receive these electrons (which is the anion, the negative ion).

The power of an element has to attract the electrons is called electronegativity, and so, as higher is the difference of electronegative of the elements, it is more probable that one of them will "still" the electrons and will form an ionic compound. The percent of this ionic character can be found by the Pauling's equation:

%IC = (1 - e^{-0.25*(x_A - x_B)^2}) *100%

Where x_A - x_B is the electronegativity difference of the elements. Thus, consulting an electronegativity table:

a. x_{Ti} = 1.5

x_{O} = 3.5

%IC = (1 - e^{-0.25*(3.5 - 1.5)^2})*100%

%IC = 63.2%

b. x_{Zn} = 1.6

x_{Te} = 2.1

%IC = (1 - e^{-0.25*(2.1 - 1.6)^2})*100%

%IC = 11.7%

c. x_{Cs} = 0.7

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 0.7)^2})*100%

%IC = 73.3%

d. x_{In} = 1.7

x_{Sb} = 1.9

%IC = (1 - e^{-0.25*(1.9 - 1.7)^2})*100%

%IC = 0.995 %

e. x_{Mg} = 1.2

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 1.2)^2})*100%

%IC = 55.5%

4 0
3 years ago
Each element consists of only one type of atom.<br> A.) True<br> B.) False
natima [27]
False there are different configurations of atoms called isotopes
7 0
3 years ago
Read 2 more answers
Below is the Lewis structure of the hydrogen cyanide molecule.
lianna [129]

Answer :

The number of bonding pairs of electrons around the hydrogen atom = 2

The number of lone pairs of electrons around the hydrogen atom = 0

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, HCN

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electrons and nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in HCN = 1 + 4 + 5 = 10

According to Lewis-dot structure we conclude that, there are 8 number of bonding electrons and 2 number of non-bonding electrons.

The number of bonding pairs of electrons around the hydrogen atom = 2

The number of lone pairs of electrons around the hydrogen atom = 0

8 0
3 years ago
A gas occupies a 1.5 L container at 25 degrees Celsius and 2.0 atm. If the gas is transferred to a 3.0 L container at the same t
harkovskaia [24]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1 x V1 / V2

P2 = 2.0 x 1.5 / 3

<span>P2 = 1 atm</span>

4 0
3 years ago
Read 2 more answers
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