Answer:
OPTION B ,COMPOUND CONTAINING AMMONIUM
Answer:
Write this in a word and skeleton equation:
Solid silver chloride and an aqueous solution of nitric acid are produced when a solution of silver nitrate is reacted with a solution of hydrochloric acid.
Explanation:
Answer:
Explanation:
conjugate acid, based on Brønsted–Lowry acid–base theory, is a chemical compound that is formed by the reception of a proton by a base
a. CH₃COOH + H₂O ⇌ H₃0⁺ + CH₃C00-
Acid <> CH₃COOH
Base <> H₂O
Conjugate acid <> H₃0 +
Conjugate base <>CH₃C00-
b. HCO₃ + H₂O ⇌ H₂CO₃⁻ + OH⁻
Acid <> H₂O
Base <> HCO₃
Conjugate acid <> H₂CO₃⁻
Conjugate base <>OH⁻
C. HNO₃ + SO₄²⁻ ⇌ HSO₄⁻ + NO₃⁻
Acid <>HNO₃
Base <>SO₄²⁻
Conjugate acid <>HSO₄⁻
Conjugate base <>NO₃⁻
A Bronsted acid is reffered to as a proton donor while a Bronsted base is a proton acceptor
Answer:
148 g
Explanation:
Step 1: Write the balanced equation for the decomposition of sodium azide
2 NaN₃ ⇒ 2 Na + 3 N₂
Step 2: Calculate the moles corresponding to 95.8 g of N₂
The molar mass of N₂ is 28.01 g/mol.
95.8 g × 1 mol/28.01 g = 3.42 mol
Step 3: Calculate the moles of NaN₃ needed to form 3.42 moles of N₂
The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.42 mol = 2.28 mol.
Step 4: Calculate the mass corresponding to 2.28 moles of NaN₃
The molar mass of NaN₃ is 65.01 g/mol.
2.28 mol × 65.01 g/mol = 148 g