Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr r

Question

2 years ago

10

espectively. Find the time taken by the slower train to pass the driver of the faster one.

1 answer:

Lemur [1.5K] · Answer 1 · 2023-08-08T00:56:55+03:00

The time taken by the slower train to pass the driver of the faster one is 24 seconds.

<h3>What is speed?</h3>

Speed is defined as the rate of change of position in unit time.

Mathematically,

Speed = Distance/Time

Now its given that,

Length of both train = 500 m

Speed of faster train = 45 km/hr

Speed of slower train = 30 km/hr

Since relative speed is the speed of a moving body with respect to another.

Hence, relative speed with respect to slower train = (45 + 30) km/hr

= 75 km/hr

In m/sec = (75*1000)/(36*36) m/sec

= 125/6 m/sec

Now since, the distance to be covered by slower to pass the driver of the faster one = length of the train

⇒ the distance to be covered by slower to pass the driver of the faster one = 500 m

Thus, required time = distance to be covered/relative speed with respect to slower train

⇒ required time = 500/(125/6) sec

or, required time = 500 * 6/125 sec

or, required time = 24 sec

Hence, The time taken by the slower train to pass the driver of the faster one is 24 seconds.

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