All categories

3 years ago

The frequency of an AM radio is 1.4 x 106 hertz (cycles per second). Approximately, how many cycles are completed in a minute?

1 answer:

5 0

There are 8,904 cycles per minute. This would be determining the amount of cycles per second, which is 148.4. After you know the amount per second, you can then multiply it by the time, which in this case is 60 seconds, or 1 minute. 148.4 cycles per second multiplied by 60 seconds is 8,904 cycles.

You might be interested in

Use synthetic division and the Remainder Theorem to find f(4) if f(x) = – 2x3 + 9x2

Elis [28]

Step-by-step explanation:

Let's see. f(4) makes the divisor x-4

4|-2 9 -6 7

| 8 -68 296

-2 17 -74 2072

The quotient is -2x²+17x-74 with a remainder of 2072

6 0

3 years ago

ANSWER AS MANY AS POSSIBLE! I WILL MARK BRAINLIEST!!!

kodGreya [7K]

Answer:

88c = -300

105c = 81300

105b = 294

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please help! File attached to this

Juliette [100K]

Answer:

C I think is the correct answer

5 0

3 years ago

1.055.

Stella [2.4K]

Given:

The statement is:

{5, 6, 7} = {5, 5, 6, 7, 7}

To find:

Whether the given statement is true or false.

Solution:

Two sets are equal if they have exactly the same elements.

The given set {5, 6, 7} has three elements and the set {5, 5, 6, 7, 7} has five elements but we known that all the elements of a set are distinct. It means, it has no repeated element.

Set {5, 5, 6, 7, 7} has three distinct elements 5, 6, 7. So,

{5, 5, 6, 7, 7} = {5, 6, 7}

Therefore, the given statement is true.

5 0

3 years ago

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

Given equation:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

To complete the square for a hyperbola

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

4 0

2 years ago