The table is:0 1 2 3
x1 0 0.08 0.06 0.04 0.00
1 0.05 0.18 0.05 0.03
2 0.05 0.04 0.10 0.06
3 0.00 0.03 0.04 0.07
4 0.00 0.01 0.05 0.06
Expected difference =
+(0.08*(0-0)) +(0.06*(0-1)) +(0.04*(0-2)) +(0.00*(0-3)) +(0.05*(1-0)) +(0.18*(1-1)) +(0.05*(1-2)) +(0.03*(1-3)) +(0.05*(2-0)) +(0.04*(2-1)) +(0.10*(2-2)) +(0.06*(2-3)) +(0.00*(3-0)) +(0.03*(3-1)) +(0.04*(3-2)) +(0.07*(3-3)) +(0.00*(4-0)) +(0.01*(4-1)) +(0.05*(4-2)) +(0.06*(4-3))
= 0.17
Answer:
i think it is A the first option
Step-by-step explanation:
Answer:
- the sample mean is 44
- the sample standard deviation is 12.35
Step-by-step explanation:
given information:
data, 
= 36.45, 67.90, 38.77, 42.18, 26.72, 50.77, 39.0, 50.23
the number of data, n = 8
the sample mean, xbar
xbar = ∑/n
= (36.45+67.90+38.77+42.18+26.72+50.77+39.0+50.23)/8
= 352.08/8
= 44
standard deviation, s
s = 
= 
= 
= 12.35
Insufficient data please indicate the question
Answer:
6 hours
Step-by-step explanation:
We can use ratios to solve
10 hours x hours
-------------- = -------------
15 logs 9 logs
Using cross products
90 = 15x
Divide by 15
90/15 = 15x/15
6 = x
6 hours
