Answer:
The probability is 0.081
Step-by-step explanation:
Here, we want to calculate the probability that the 3rd inspection will be defective.
What this means is that the first two would
not be defective.
Probability of having a defective DVD = 10% = 10/100 = 0.1
Probability of not having a defective DVD = 1 -0.1 = 0.9
So the probability of third being defective = Probability of first not defective * Probability of second not defective * Probability of third defective
= 0.9 * 0.9 * 0.1 = 0.081
Answer:
Ok, here goes: f(3) means take f(x) and plug in 3 wherever we see x. So
f(3) = 12*39 + 3 = 236196 + 3
f(3) = 236199
Likewise, f(-3) means take f(x) and plug in (-3) wherever we see x. So
f(-3) = 12*(-3)9 + (-3) = -236196 - 3
f(-3) = -236199
Putting those two things together, we get
f(3) + f(-3) = 236199 - 236199 = 0
Step-by-step explanation:
4) (log3)14/(log3)4
hope dis helps<span />
First of all we have to arrange the data in ascending order as shown below:
28, 40, 43, 43, 45, 50, 50
Total number of values = 7
Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:
1st Half = 28, 40, 43
2nd Half = 45, 50, 50
Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.
IQR or the Inter Quartile Range is the difference of Q3 and Q1.
So, IQR= Q3 – Q1 = 50 – 40 = 10
Thus, IQR for the given data is 10
