Answer:
The circulation of the field f(x) over curve C is Zero
Step-by-step explanation:
The function
and curve C is ellipse of equation

Theory: Stokes Theorem is given by:

Where, Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5CF1%26F2%26F3%5Cend%7Barray%7D%5Cright%5D)
Also, f(x) = (F1,F2,F3)

Using Stokes Theorem,
Surface is given by g(x) = 
Therefore, tex]\hat{N} = grad(g(x))[/tex]


Now, 
Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5CF1%26F2%26F3%5Cend%7Barray%7D%5Cright%5D)
Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5Cx%5E%7B2%7D%264x%26z%5E%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
Curl f(x) = (0,0,4)
Putting all values in Stokes Theorem,



I=0
Thus, The circulation of the field f(x) over curve C is Zero
I am pretty sure it is $400. sorry if i’m wrong
Answer:
The minimum sample size is 
Step-by-step explanation:
From the question we are told that
The confidence interval is 
The margin of error is 
Generally the sample proportion can be mathematically evaluated as



Given that the confidence level is 98% then the level of significance can be mathematically evaluated as



Next we obtain the critical value of
from the normal distribution table
The value is

Generally the minimum sample size is evaluated as
![n =[ \frac { Z_{\frac{\alpha }{2} }}{E} ]^2 * \r p (1- \r p )](https://tex.z-dn.net/?f=n%20%20%3D%5B%20%5Cfrac%20%7B%20Z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20%20%5Cr%20p%20%281-%20%5Cr%20p%20%29)
![n =[ \frac { 2.33}{0.1} ]^2 * 0.475(1- 0.475 )](https://tex.z-dn.net/?f=n%20%20%3D%5B%20%5Cfrac%20%7B%202.33%7D%7B0.1%7D%20%5D%5E2%20%2A%20%200.475%281-%200.475%20%29)

Answer and Step-by-step explanation:
Distance is the numerical measurement to find the space or interval between two objects. Distance also refers to physical length. Point x to point y distance is denoted as |xy|
There are many ways to find out the distance, distance between two objects or two points. The efficient way of finding the distance between two points is given below. Mathematically, the distance between two points on a coordinate plane can be determined by using the distance formula, which is:
d =√((x2-x1)2+(y2-y1)2),
Where (x1, y1) and (x2, y2) coordinates, and d is the distance.
The middle point between these two points is known as midpoint and can find out by using the formula
Midpoint = a + b /2.
The distance between two points number line can also be calculated by using the formula:
AB =|b –a| or |a-b|.