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3 years ago

Factoring trinomials

Mathematics

1 answer:

Kobotan [32]3 years ago

3 0

Answer:

Trinomial

Step-by-step explanation:

Hope it helps

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Please help ill give brainliest answer!

LenKa [72]

Answer:

OC=48

RK=100

Step-by-step explanation:

We can use proportions to find both OC and RK.

$\frac{OK}{KY} =\frac{OC}{RY}$

$\frac{12}{24} =\frac{OC}{96}$

$24OC=1152$

$OC=48$

$\frac{KC}{RK} =\frac{OK}{KY}$

$\frac{50}{RK} =\frac{12}{24}$

$12RK=1200$

$RK=100$

7 0

3 years ago

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What is the domain of the function;<br> y= (x-1)2 -2

valkas [14]

It should be 2 but i’m not positive

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3 years ago

Label 1/4 on the number line. Label 1/2 on the number line .

KIM [24]

Answer:

it goes 0 then 1/4 in the first notch 1/2 in the second notch 3/4 in the third notch then the number 1 on the fourth

Step-by-step explanation:

Hope that helps.

5 0

3 years ago

The vocbulary of adding and subtracting radicals

motikmotik

Adding and subtracting radical expressions.

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3 years ago

Use a paragraph, flow chart, or two-column proof to prove the angle congruency. Given: ∠ CXY ≅ ∠ BXY

Llana [10]

Answer:

See explanation

Step-by-step explanation:

Consider triangles CAX and BAX. In these triangles,

$\overline{AC}\cong \overline{AB}$ - given
$\angle CAX\cong \angle BAX$ - given
$\overline{AX}\cong \overline{AX}$ - reflexive property

By SAS postulate, $\triangle CAX\cong \triangle BAX$

Congruent triangles have conruent corresponding parts. So,

$\overline{CX}\cong \overline{BX}$

Consider triangles CXY and BXY. In these triangles,

$\overline{CX}\cong \overline{BX}$ - proven
$\angle CXY\cong \angle BXY$ - given
$\overline{XY}\cong \overline{XY}$ - reflexive property

By SAS postulate, $\triangle CXY\cong \triangle BXY$

Congruent triangles have conruent corresponding parts. So,

$\angle XCY\cong \angle XBY$

5 0

3 years ago