Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
The answer to the solution of the equation 5x+2y=-1 is 1,-3)
The answer is A. It says that circle b is 16 times greater so yeah its A.
You are given the X value, replace x with 2 in the first equation to solve for y:
y=2x +3
y = 2(2) +3
y = 4+3
y = 7
Now replace y with 7 and x iwth 2 in the second equation and solve for k:
y = -x +k
7 = -2 +k
Add 2 to both sides:
9 = k
so k = 9
The point is given as k-2, which is 9-2 = 7, which is what y equals in the first equation.
K = 9
Answer:
-3.7
Step-by-step explanation:
-3.2 + 1.5 -2 = -3.7
