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ser-zykov [4K]
1 year ago
7

Abc(3) if a= -6 b= -4 c=3 PLEASE ANSWER

Mathematics
2 answers:
Sergeeva-Olga [200]1 year ago
8 0

is = 216

Step-by-step explanation:

A

a=-6 b=-4 c=3 =216

irina [24]1 year ago
6 0
Depends on what you’re asking here. if the equation is abc then it’s 72. it’s it’s abc(3) then it’s 216.

abc= (-6)(-4)(3)=72
but
abc(3)= (-6)(-4)(3)(3)= 216
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Maddie biked 8 3/4 miles today, and Chase bikes 3 1/2 miles. How many times the length of Chase’s bike ride was Maddie’s bike ri
borishaifa [10]

Answer: 2.5 times

Step-by-step explanation:

Given : The length of Chase’s bike ride= 8\dfrac{3}{4}\ miles

The length of Maddie’s bike ride=3\dfrac{1}{2}\ miles

In improper fraction : Length of Chase’s bike ride=\dfrac{4(8)+3}{4}\ miles

=\dfrac{35}{4}\ miles

Similarly , Length of Maddie’s bike ride= \dfrac{7}{2}\ miles

The number of times the length of Chase’s bike ride was Maddie’s bike ride= \dfrac{\text{ Length of Chase’s bike ride}}{\text{ Length of Maddie’s bike ride}}

=\dfrac{\dfrac{35}{4}}{\dfrac{7}{2}}\\\\=\dfrac{5}{2}=2.5

Hence, the length of Chase’s bike ride was 2.5 times Maddie’s bike ride.

8 0
3 years ago
What is 4/5 of 45 equle
Goryan [66]
\frac{4}{5} \ of \ 45= \frac{4}{5} \times 45=4 \times \frac{45}{5}=4 \times 9=36

4/5 of 45 equals 36.
5 0
3 years ago
Read 2 more answers
Is 1/3+ 5 perpendicular
MrRa [10]

Answer:

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3 0
3 years ago
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Mr. Cruz fills a 3-gallon water cooler for a family picnic. He brings plastic cups that each hold 12 fluid ounces of water. How
oksian1 [2.3K]

One gallon is equivalent to 128 fluid ounces

3 gallons is equivalent to 3*128 fluid ounces

= 384 fluid ounces

One plastic cup can hold 12 guide ounces

So cups needed will be 384/12

32 cups

8 0
2 years ago
Complete the table for the radioactive iotope. (Round your anwer to 2 decimal place. Iotope : 239 Pu
Marizza181 [45]

If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams

The half life in years = 24100

Consider the quantity of the radio active isotope remaining

y = Ce^{kt}

When t = 1000 the y = 1.2

y = C/2 when t = 1599

Substitute the values in the equation

C/2 = Ce^{24100k}

Cancel the C in both side

1/2 = e^{24100k}

Here we have to apply ln to eliminate the e terms

ln (1/2) = 24100k

k = ln(1/2) / 24100

k = -2.87× 10^-5

To find the initial value we have to substitute the value of k and y in the equation

1.2 = Ce^{1000 ×  -2.87× 10^-5}

C = 1.2 / e^(-0.0287)

C = 2.16 gram

Hence, the initial quantity of the radioactive isotope is 2.16 gram

Learn more about half life here

brainly.com/question/4318844

#SPJ4

7 0
1 year ago
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