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3 years ago

Come up with five solutions for the equation below: y = 3x + 2

Mathematics

2 answers:

notka56 [123]3 years ago

7 0

(0,2)
(1,5)
(2,8)
(3,11)
(4,14)

marusya05 [52]3 years ago

3 0

Step-by-step explanation:

1/3y=x+2/3

1=x/y+2/y

3x=y-2

x=1/3y-2

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I am an improper fraction whose numerator and denominator are made of odd digits only. In my simplest form, my representation as

ASHA 777 [7]

Answer:

The fraction is = $\frac{21}{9}$

Step-by-step explanation:

In simplest form the fraction is represented in mixed number as $2\frac{1}{3}$ .

The fraction form of the mixed number can be given as :

$2\frac{1}{3}=\frac{7}{3}$

Let the fraction be = $\frac{7x}{3x}$ [As multiplying same numbers to numerator and denominator does not affect the proportion.

Sum of numerator and denominator is = 30

This, can be represented as:

$7x+3x=30$

Solving for $x$ .

$10x=30$

Dividing both sides by 10.

$\frac{10x}{10}=\frac{30}{10}$

$x=3$

So, the fraction will be = $\frac{7\times 3}{3\times 3}$

⇒ $\frac{21}{9}$

3 0

3 years ago

Keep answer in fraction form. Use < &> in your solution set. Solve for b.Give an exact answer in simplified form. 30b

Fed [463]

I do not know the answer but i need to answer a question in order to ask one,sorry,hope u understand:/

7 0

3 years ago

Jessica can walk 1.5 kilometers in 30 minutes. How long will it take her to walk 2.5 kilometers?

RUDIKE [14]

Answer:

It should be 20minutes at a easy pace

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

In ΔOPQ, the measure of ∠Q=90°, OQ = 80, QP = 39, and PO = 89. What ratio represents the cosecant of ∠P?

Serjik [45]

Answer:

cos(O) = 39 / 89

Step-by-step explanation:

Given:

ΔOPQ, where

∠Q=90°

PO = 89

OQ = 39

QP = 80

cosine of ∠O?

cos(O) = Adjacent / Hypotenuse

cos(O) = 39 / 89

3 0

3 years ago

Read 2 more answers

Helppppppppppppppppppp please

Svetlanka [38]

Answer:

$\sqrt[]{\frac{x+8}{4}}-3$

Step-by-step explanation:

$g(x)=4(x+3)^2-8$

First rewrite $g(x)$ as y

$y=4(x+3)^2-8$

Now swap y and x

$x=4(y+3)^2-8$

Add 8 on both sides.

$x+8=4(y+3)^2-8+8$

$x+8=4(y+3)^2$

Divide by 4.

$\frac{x+8}{4} =\frac{4(y+3)^2}{4}$

$\frac{x+8}{4}=(y+3)^2$

Extract the square root on both sides.

$\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}$

$\sqrt[]{\frac{x+8}{4}}=y+3$

Subtract 3 on both sides.

$\sqrt[]{\frac{x+8}{4}}-3=y+3-3$

$\sqrt[]{\frac{x+8}{4}}-3=y$

4 0

3 years ago