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3 years ago

Come up with five solutions for the equation below: y = 3x + 2

Mathematics

2 answers:

notka56 [123]3 years ago

7 0

(0,2)
(1,5)
(2,8)
(3,11)
(4,14)

marusya05 [52]3 years ago

3 0

Step-by-step explanation:

1/3y=x+2/3

1=x/y+2/y

3x=y-2

x=1/3y-2

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Number 53

Solnce55 [7]

X-intercepts
f(x) = 0

4x² - 15x - 4 = 0

4x² - 16x + x - 4 = 0

4x(x - 4) + 1(x - 4) = 0

(x - 4)(4x + 1) = 0 ⇔ x - 4 = 0 or 4x + 1 = 0

x = 4 or 4x = - 1 ⇒ x = - 1/4

Answer: -1/4 and 4.

8 0

3 years ago

PLEASE SOMEONE HELP ME

mylen [45]

Answer:

Step-by-step explanation:

4 0

2 years ago

If Ben invests $4500 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that

pogonyaev

$Step \; 1: \; Assing \; variable \; for \; the \; unknown \; that \; we \; need \; to \; find.\\Let \; x \; be \; additional \; money \; invested$

$Step \; 2: \; Use \; the \; appropriate \; formula \; of \; simple \; interest \; set \; up \; an \; equation\\Interest \; earned \; each \; year = \; Amount \; invested \times annual \; rate \; of \; interest\\\\Amount \; invested \; in \; 4 \% \; rate \; of \; interest=\$4500\\Amount \; invested \; in \; 5\frac{1}{2}\% \; rate \; of \; interest= \$x\\Amount \; invested \; totally \; in \; 4\frac{1}{2}\% \; rate \; of \; interest = \$(4500+x)$

$Interest \; earned \; in \; 4\% \; interest \; rate\\ = \; 4500(4\%)=180\\Interest \; earned \; in \; 5\frac{1}{2}\% \; interest \; rate\\ = x(5\frac{1}{2}\%)=0.055x\\Interest \; earned \; totally \; in \; 4\frac{1}{2}\% \; interest \; rate = (4500+x)(4\frac{1}{2}\%)\\=0.045(4500+x)$

$\\\\So, \; the \; equation \; would \; be:\\180+0.055x=0.045(4500+x)$

$Step \; 1: \; Distribute \; 0.045 \; in \; the \; right \; side\\180+0.055x=202.5+0.045x\\\\Step \; 2: \; Subtract \; 0.045x \; and \; 180 \; on \; both \; sides \; to \; get \; x \; alone\\0.055x-0.045x=202.5-180\\\\Step \; 3: \; Combine \; Like \; Terms\\0.01x=22.5\\\\Step \; 4: Divide \; 0.01 \; on \; both \; sides\\\frac{0.01x}{0.01}=\frac{22.5}{0.01}\\\\Step \; 5: \; Simplifying \; fraction \; on \; both \; sides\\x=2250$

$\underline{Conclusion:}\\Ben \; should \; invest \; additional \; money \; of \; \$2250$

5 0

3 years ago

Complete the statement using always, sometimes, or never.

Fynjy0 [20]

I believe that, "A quadrilateral is sometimes a trapezoid”.

5 0

2 years ago

Can someone solve the system of equations?

kogti [31]

Y=x^2-5

y=2x-5
y+5=2x
x=(y+5)/2

y=((y+5)/2)^2-5
y=(y^2+10y+25)/4-5
4y=y^2+10y+25-20
0=y^2+6y+5
0=(y+5)(y+1)
y= -5 or -1

y=2x-5 (y= -5 doesn't work for this one so use -1)
-1=2x-5
2x=4
x=2

Using these answers, you can choose answer D with reasonable certainty.

5 0

2 years ago