Question

(b) Ozone absorbs radiation of wavelengths 2200–2900 Å, thus protecting organisms from this radiation. Find the frequency and energy of the most energetic of these photons.

Answer 1

The frequency and energy of most energetic of these photons is$1.36*10^{15}$ Hz and $9.04*10^{-19}$ J respectively.

The high energy photons will have least wavelength. Taking the given less wavelength for calculation of frequency and energy of photons.

λ = 2200  Å

Also, we know, 1 Å = $10^{-10}$ m

So, λ = $2200*10^{-10}$

λ = $2.2*10^{-7}$ m

Now, calculating frequency using the formula -

c = fλ, where c is speed of light, f is frequency and λ is wavelength.

We know, c = $3*10^{8}$ m/s

f = c/λ

f = $\frac{3*10^{8} }{2.2*10^{-7} }$

frequency = $1.36*10^{15}$ Hz

Now, calculating Energy through the formula -

E = hf, where E is energy, h is planck's constant and f is frequency

Value of planck's constant = $6.63*10^{-34}$ Js

E = $6.63*10^{-34}$*$1.36*10^{15}$

Energy = $9.04*10^{-19}$ J

Thus, frequency and energy of photons is $1.36*10^{15}$ Hz and $9.04*10^{-19}$ J respectively.

Learn more about energy of photon -

brainly.com/question/15946945

#SPJ4