Answer:
$6 = cost of small box
$8 = cost of large box
Step-by-step explanation:
Let s = cost of small box
l = cost of large box
(1) 12s + 3l = 96 (2) 6s + 6l = 84
Multiply by -2 <u> -24s - 6l = -192</u>
-18s = - 108
s = $6 = cost of small box
12(6) + 3l = 96
72 + 3l = 96
3l = 24
l = $8 = cost of large box
Answer:
I dont know if this will help or not but
Step-by-step explanation:
Answer:
Descarte's rule says that the polynomial will have the number of zeroes equal to the number of times the sign off the coefficient changes.
For positive real roots:

The coefficient of polynomial is:
+9 -4 +10
There is 2 time sign in changing in 1st and 2nd term and then in 2nd and 3rd term.
So,there will be 2 positive real roots or less but even.
For negative real roots find P(-x)


So, coefficient of above polynomial is:
-9 +4 -10
There is 2 time sign in changing in 1st and 2nd term and then in 2nd and 3rd term.
So,there will be 2 negative real roots or less but even.
Answer: 1180
Step-by-step explanation: 4 20 dirhams mean :20+20+20+20= 80
5 100 dirhams mean:100+100+100+100+100=500
3 200 dirhams mean; 200+200+200= 600
so,80+500+600=1180
Split the middle term.
(2n²-5n)-42
Multiply the coefficient of the first term (2 is the coefficient of 2n²) by the constant (-42, it's constant because there are no variables attached).
2 x (-42) = -84
Find the factor of -84 that equals your middle term (-5)
The factors of 84 are as follows (remember that if either number is negative, you'll get -84):
84*1
42*2
28*3
21*4
14*6
12*7
What two numbers, when added or subtracted, equal the middle term? 12-7 = 5, but your number is a negative, so how do you do get that 5 to be negative? -12+7 = -5, but make that easier to understand 7-12 = -5, and now add your variable back to get 7n-12n = -5n
Rewrite your equation using the split middle term.
2n²+7n-12n-42
Pull out the factors and add up the first two terms.
n*(2n+7) = 2²+7n
-6(2n+7) = -12n-42
The numbers inside the parenthesis give you one half of your new equation, combine the numbers outside the parentheses to get your second half.
(n-6) (2n+7)
In regards to your answer, there are three possibilities:
1) You wrote the initial equation incorrectly
2) You wrote the answers incorrectly
3) Whoever created the question wrote the equation or the answers wrong, and the answer is not present.