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Setler [38]
3 years ago
9

Determine whether each equation is an identity or whether it has no solution. 6x+1=6x-8

Mathematics
2 answers:
Tatiana [17]3 years ago
5 0
Minus 6x both sides
1=-8
false
no soluion
erma4kov [3.2K]3 years ago
3 0

no soltion to this question sorry

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Factor y + 5y + 6.<br> ??
maxonik [38]

Answer:

6(y+1)  Hope this helps!!

Step-by-step explanation:

6 0
3 years ago
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Karen is 6 years older than her sister Michelle, and Michelle is 2 years younger than their brother David. If the sum of their a
ale4655 [162]
K\ \rightarrow\ the\ Karen's\ age\\M\ \rightarrow\ the\ Michelles\ age \\D\ \rightarrow\ the\ David's\ age\\\\K=M+6\\M=D-2\ \ \ \Rightarrow\ \ \ D=M+2\\K+M+D=62\\\\(M+6)+M+(M+2)=62\\3M+8=62\\3M=54\ /:3\\M=18\ \ \ \Rightarrow\ \ \ K=18+6=24\ \ \ and\ \ \ D=18+2=20\\\\Ans.\ Michelle\ is\ 18,\ David\ is\ 20,\ Karen\ is\ 24.
6 0
3 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
2 years ago
CD has endpoints C(-3, 4) and D(1, -2). Find the coordinates<br> of its midpoint.
Natalija [7]

Answer:

Midpoint (-1 , 1)

Step-by-step explanation:

Formula: (midpoint)

Let the point A(x , y) be the midpoint of CD.

x=\frac{x_c+x_D}{2} =\frac{-3+1}{2} =\frac{-2}{2} =-1

y=\frac{x_C + y_D}{2} =\frac{4+(-2)}{2} =\frac{2}{2} =1

Then

A(-1 , 1)

4 0
2 years ago
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Whats the percent change of 13.7 to 40.2
k0ka [10]

The percent change of 13.7 to 40.2 is 193.4%

To find percentage change, you need to find the difference between the two numbers. In this case, 26.5.

You then divide 26.5 by 13.7 and move the decimal point two spaces to the right.

6 0
3 years ago
Read 2 more answers
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