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timurjin [86]
1 year ago
10

After 4th collision in ethernet, find the maximum time that the adapter waits until sensing the channel again for a 100 mbps bro

adcast channel?
Computers and Technology
1 answer:
VARVARA [1.3K]1 year ago
3 0

Waiting time for a 100 Mbps broadcast channel is 0.512 ms

Recall that with the CSMA/CD protocol, the adapter waits K * 512 bit times after a collision,

where K is drawn randomly. For K = 100,

The one bit time for 10 Mbps is 1/10000000 s = 0.0001 ms

The one bit time for 100 Mbps is 1/100000000 s = 0.00001 ms

Waiting time for a 10 Mbps broadcast channel is K*512*0.0001= 5.12 ms

Waiting time for a 100 Mbps broadcast channel is K*512*0.00001= 0.512 ms

<h3>What is a collision in Ethernet?</h3>
  • A collision happens on a half-duplex Ethernet network when two devices on the same network attempt to communicate data at the exact same time.
  • The two transmitted packets are "collapsed" by the network, which results in the network discarding both of them.
  • On Ethernets, collisions are unavoidable.
  • A collision is a momentary interaction between two bodies or more than two bodies at once that modifies the motion of the bodies involved as a result of the internal forces at work.
  • Collisions entail the application of force (there is a change in velocity).

Learn more about collision in Ethernet: brainly.com/question/14123270

#SPJ4

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<h3>Writting in C++ code:</h3>

<em />

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<em>using namespace std;</em>

<em>bool isPrime(int n){</em>

<em>   for(int i = 2; i < n/2; i++){</em>

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<em>   }</em>

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<em>   int sumVal = 0;</em>

<em>   for(float i = 2; i <= n; i++){</em>

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<em>   }</em>

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<em>}</em>

<em>int main(){</em>

<em>   int n = 15;</em>

<em>   cout<<"The sum of prime number between 1 to "<<n<<" is "<<findPrimeSum(n);</em>

<em>   return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

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