On a graph, move 2 spaces to the right and from there move 18 spaces down. Now, where you've ended, make a dot. The distance fro the origin is -2/18 (as a fraction).
Answer:
Its outfile<<number.
However, before this we need to write
outfile.open("xyz.txt", ios;;out)
outfile<<number
And this code will do what is required in the question. This is going to write the number's content to the xyz.txt file which is the file associated with the outfile.
And remember this is in C++. And C++ is a imperative oriented programming language. Undoubtedly, Python and R are fully object oriented programming languages.
Explanation:
The answer is self explanatory.
The answers are /var/lib/dhcpd/dhcpd.leases & /var/lib/dhcpd/dhcpd6.leases
In order to look up ipv4 and ipv6 dhcp leases, The two files that should be viewed are /var/lib/dhcpd/dhcpd.leases & /var/lib/dhcpd/dhcpd6.leases
The answer to this should be B. Worm. A pinion is a the smallest gear out of the listed ones above. spur would be next then wheel and the biggest if them all would be the spur. I'm not completely sure if my answer is 100% correct, but I feel confident enough about it. Hope this helps. :)
Answer:
//Code is created using java
import java.util.*;
// returns the sum
public int sum(int N)
{
if(N==1)
return (1);
else
return N+sum(N-1);
}
// code to return the Bipower ouput
public int BiPower(int N)
{
if(N==1)
return (2);
else
return 2*BiPower(N-1);
}
// Code to return TimesFive output
public int TimesFive(int N)
{
if(N==1)
return 5;
else
return 5 + timesFive(N-1);
}
public static void main(String args[])
{
//Prompts the user to enter a nonnegative integer
int N = Integer.parseInt.(console.readLine("Enter a nonnegative integer: "));
//Outputs the sum, Bipower and TimesFive
System.out.println(sum(n));
System.out.println(BiPower(n));
System.out.println(TimesFive(n));
}
}
