The value of h(t) when
is 10.02.
Solution:
Given function 
To find the value of h(t) when
:

Substitute
in the given function.


Now multiply the common terms into inside the bracket.

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64




= 10.02

Hence the value of h(t) when
is 10.02.
The answer is Eight ninetieths
Pls mark as brainliest thx
As you know, 4.78 is less than 5, so
.. yes, x=4.78 is a solution to x < 5
As you know, 6 = 6, but is not less than 6.
.. no, x=6 is not a solution to x < 6.