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pishuonlain [190]
4 years ago
10

Solve using the quadratic formula... 9x2 - 4 + 7x

Mathematics
2 answers:
Evgen [1.6K]4 years ago
8 0

Answer:

x=0.4, x=-1.2

Step-by-step explanation:

jeka944 years ago
3 0

Answer:

x=-\frac{7}{18}+\frac{\sqrt[]{193} }{18} which is the same as x=0.38

or

x=-\frac{7}{18}-\frac{\sqrt[]{193} }{18} which is the same as x=-1.16

Step-by-step explanation:

9x^2-4+7x=0

Rearranging...

9x^2+7x-4=0

a=9

b=7

c=-4

x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac}  }{2a}

x=\frac{-7\frac{+}{}\sqrt[]{(7)^2-4(9)(-4)}  }{2(9)}

x=\frac{-7\frac{+}{}\sqrt[]{49+144}  }{18}

x=\frac{-7\frac{+}{}\sqrt[]{193}  }{18}

----------------------------------------

x=-\frac{7}{18}+\frac{\sqrt[]{193} }{18}

or

x=-\frac{7}{18}-\frac{\sqrt[]{193} }{18}

-------------------------------------------

If you need decimals, you can solve;

x=0.38\\

or

x=-1.16

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Step-by-step explanation:

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4 years ago
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0
3 years ago
?
statuscvo [17]
S=θr
10.91=θ5
10.91/5=θ
therefore
θpie/180= your answer in radians
8 0
3 years ago
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