The centre and radius of the equation are (-2, 3) and 3 units respectively
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as;
x^2+y^2+2gx+2fy+C = 0
Given the equation
(x^2 + 4x) + (y^2 − 6y) = −4
Complete the squares
(x^2+4x+4)-4+(y^2-6y+9)-9 = -4
(x+2)^2+(y-3)^2=-4+13
(x+2)^2+(y-3)^2 = 9
(x+2)^2+(y-3)^2 = 3^2
Hence the centre and radius of the equation are (-2, 3) and 3 units respectively
Learn more on equation of circle here: brainly.com/question/1559324
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