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Oliga [24]
2 years ago
13

Complete the square to rewrite the following equation. Identify the center and radius of the circle. You must show all work and

calculations
x2 + 4x + y2 − 6y = −4
Mathematics
1 answer:
Travka [436]2 years ago
8 0

The centre and radius of the equation are (-2, 3) and 3 units respectively

<h3>Equation of a circle</h3>

The standard equation of a circle is expressed as;

x^2+y^2+2gx+2fy+C = 0

Given the equation

(x^2 + 4x) + (y^2 − 6y) = −4

Complete the squares

(x^2+4x+4)-4+(y^2-6y+9)-9 = -4

(x+2)^2+(y-3)^2=-4+13

(x+2)^2+(y-3)^2 = 9

(x+2)^2+(y-3)^2 = 3^2

Hence the centre and radius of the equation are (-2, 3) and 3 units respectively

Learn more on equation of circle here: brainly.com/question/1559324

#SPJ1

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I need to find the missing numbers
const2013 [10]

Answer:

b11 = -14

b12 = 9

b13 = 8

Step-by-step explanation:

* Lets revise some notes to solve the problem

- Any matrix has a dimension m × n, where m is the number of rows

 and n the number of columns

- We can add matrices with same dimensions

* Now lets solve the problem

∵ B+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]

- Let B=\left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]

∴ \left[\begin{array}{ccc}b11&b12&b13\\b21&b22&b23\end{array}\right]+\left[\begin{array}{ccc}15&-7&4\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}1&2&12\\4&0&2\end{array}\right]

- Lets add and find the missing

* Lets start with the first rows

∵ b11 + 15 = 1 ⇒ subtract 15 from both sides

∴ b11 = -14

∵ b12 + -7 = 2 ⇒ add 7 to both sides

∴ b12 = 9

∵ b13 + 4 = 12 ⇒ subtract 4 from both sides

∴ b13 = 8

* Now lets start with the second rows

∵ b21 + 0 = 4

∴ b21 = 4 ⇒ given

∵ b22 + 1 = 0 ⇒ subtract 1 from both sides

∴ b22 = -1 ⇒ given

∵ b23 + 2 = 2 ⇒ subtract 2 from both sides

∴ b23 = 0 ⇒ given

5 0
3 years ago
Select the polynomial that can be factored as (4x-5)(16x^2+20x+25)
bezimeni [28]

f(x) = 64x³ - 125

Multiply each term in the second factor by each term in the first factor

= 4x(16x² + 20x + 25) - 5(16x² + 20 x + 25)

=64x³ + 80x² + 100x - 80x² - 100x - 125

= 64x³ - 125 ← difference of cubes




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