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frez [133]
1 year ago
6

Please help me solve this before 8pm today please!!!!!

Mathematics
1 answer:
Nastasia [14]1 year ago
8 0

Answer: x=10

Step-by-step explanation:

7776^{x+5}=216^{3x-5}

6^{5(x+5)}=6^{3(3x-5)}

5(x+5)=3(3x-5)

5x+25=9x-15

25=4x-15

4x=40

x=10

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Which phrase matches the algebraic expression below 3(x+7)+10
Vladimir79 [104]
Which ever expression is 3x + 21 + 10 ..... 21 + 10 = 31 .... So it'll be 3x + 31 .
8 0
2 years ago
Does the point (2,3) satisfy the inequality 4x+3y> 20
adell [148]
No, (2 , 3) does not satisfy the inequality 4x + 3y > 20.

See attached picture:

~

5 0
3 years ago
Find the first term of the sequence 4, 12, 36, 108.... which exceeds 20,000.
Schach [20]

Answer:

43740

Step-by-step explanation:

its an exponential factor of 3 just multiply each answer by 3 to get the next one up

5 0
2 years ago
Can someone PLEASE help me with this question?
disa [49]

9514 1404 393

Answer:

  11

Step-by-step explanation:

The future value of the account is given by the formula ...

  A = P(1 +r/12)^(12t) . . . . principal P invested at rate r for t years

Solving for t, we find ...

  A/P = (1 +r/12)^(12t) . . . . . . . . . . . divide by P

  log(A/P) = 12t·log(1 +r/12) . . . . . . take logs

Divide by the coefficient of t, then fill in the numbers.

  t = log(A/P)/(12·log(1 +r/12)) = log(202800/93000)/(12·log(1 +.068/12))

  t ≈ 11.497

It will take about 11 years for the account balance to reach the desired amount.

4 0
2 years ago
Two miners are trying to push a stationary mine cart filled with gold. Miner A is exerting 25 N while miner B is exerting 20 N.
Oliga [24]

Answer:

b. 45 N

Step-by-step explanation:

The sum of the forces exerted by the two miners = 25 + 20

                                           = 45 N

Since after applying a force of 45 N by the two miners the cart remained stationary, it implies that a resistance force of at least 45 N acts against their push. Thus, the force exerted by the road could be equal to 45 N or greater than 45 N.

Probably, if the sum of the forces applied is 46 N, the cart would move. Which depends on the value of resistance force applied by the road. Thus, the appropriate answer from the given option is B.

Since the force applied on the cart equals the resistance force exerted by the road, the cart would not move.

6 0
2 years ago
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