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Kipish [7]
3 years ago
9

Which of these describes the function graphed below

Mathematics
1 answer:
Allisa [31]3 years ago
5 0

Answer:

B

Step-by-step explanation:

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Is 1.88 rational or is it irrational
Anna11 [10]

Answer:

1.88 is a irrational number

3 0
3 years ago
What are the first three common multiples of 3 and 7?
Alexeev081 [22]

3 - 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63

7 - 7, 14, 21, 28, 35, 42, 49, 56, 63

First three common multiples of 3 and 7 are 21, 42, and 63.

Answer - 21, 42, 63

Hope this Helps!!

8 0
3 years ago
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Find the area, circumference =6pi yd
vitfil [10]
Circumference = 2πr

Given that circumference 0s 6π, find radius:
2πr = 6π
r = 6π ÷ 2π = 3

Now that we know that the radius is 3 yard, find area:
Area = πr²
Area = π(3)²
Area = 9π = 28.27 yd²

Answer: 28.27 yd²
7 0
3 years ago
A baker buys 10 apples from a farmer for $.25/each. the baker uses the 10 apples to make an apple pie that they sell in their ba
RUDIKE [14]

The total contribution to the GDP is $5.49.

<h3>How to find the total contribution to GDP?</h3>

GDP, the gross domestic product is the sum of all final goods and services produced in an economy within a given period.

When calculating GDP, only the value added of final goods and services are included. Intermediate goods are not added.

Therefore,

Total contribution to GDP = 7.99 - (10 X 0.25) = $5.49.

learn more GDP here: brainly.com/question/27982341

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6 0
2 years ago
Jamal simplified the expression √75x^5y^8 where x≥ 0 and y≥0. √75x^5y^8 = √25 times 3 times x^4 times x times y^8 = 5x^2y^2 √3x
Scorpion4ik [409]

Answer:

He should have written the square root of y^8 in the answer as y^4, not y^2

Step-by-step explanation:

We need to remember that:

\sqrt[n]{x^n}=x

The Product of powers property states that:

(a^m)(a^n)=a^{(m+n)}

The Power of a power a property states that:

(a^m)^n=a^{(mn)}

Let's check the procedure made by Jamal to simplify the expression \sqrt{75x^5y^8 } where x\geq0 and y\geq0:

=\sqrt{25*3*x^4*x*y^8} (This is correct)

5x^2y^2\sqrt{3x} (Jamal made a mistake)

The correct procedure is:

=\sqrt{25*3*x^4*x*y^8}

=5x^2y^4\sqrt{3x}

Because:

\sqrt{y^8}=\sqrt{(y^4)^2}=y^4

Therefore: He should have written the square root of y^8 in the answer as y^4, not y^2,

5 0
3 years ago
Read 2 more answers
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