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3 years ago

Which of these describes the function graphed below

Mathematics

1 answer:

Allisa [31]3 years ago

5 0

Answer:

Step-by-step explanation:

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Is 1.88 rational or is it irrational

Anna11 [10]

Answer:

1.88 is a irrational number

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3 years ago

What are the first three common multiples of 3 and 7?

Alexeev081 [22]

3 - 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63

7 - 7, 14, 21, 28, 35, 42, 49, 56, 63

First three common multiples of 3 and 7 are 21, 42, and 63.

Answer - 21, 42, 63

Hope this Helps!!

8 0

3 years ago

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Find the area, circumference =6pi yd

vitfil [10]

Circumference = 2πr

Given that circumference 0s 6π, find radius:
2πr = 6π
r = 6π ÷ 2π = 3

Now that we know that the radius is 3 yard, find area:
Area = πr²
Area = π(3)²
Area = 9π = 28.27 yd²

Answer: 28.27 yd²

7 0

3 years ago

A baker buys 10 apples from a farmer for $.25/each. the baker uses the 10 apples to make an apple pie that they sell in their ba

RUDIKE [14]

The total contribution to the GDP is $5.49.

<h3>How to find the total contribution to GDP?</h3>

GDP, the gross domestic product is the sum of all final goods and services produced in an economy within a given period.

When calculating GDP, only the value added of final goods and services are included. Intermediate goods are not added.

Therefore,

Total contribution to GDP = 7.99 - (10 X 0.25) = $5.49.

learn more GDP here: brainly.com/question/27982341

#SPJ1

6 0

2 years ago

Jamal simplified the expression √75x^5y^8 where x≥ 0 and y≥0. √75x^5y^8 = √25 times 3 times x^4 times x times y^8 = 5x^2y^2 √3x

Scorpion4ik [409]

Answer:

He should have written the square root of $y^8$ in the answer as $y^4$ , not $y^2$

Step-by-step explanation:

We need to remember that:

$\sqrt[n]{x^n}=x$

The Product of powers property states that:

$(a^m)(a^n)=a^{(m+n)}$

The Power of a power a property states that:

$(a^m)^n=a^{(mn)}$

Let's check the procedure made by Jamal to simplify the expression $\sqrt{75x^5y^8 }$ where $x\geq0$ and $y\geq0$ :

$=\sqrt{25*3*x^4*x*y^8}$ (This is correct)

$5x^2y^2\sqrt{3x}$ (Jamal made a mistake)

The correct procedure is:

$=\sqrt{25*3*x^4*x*y^8}$

$=5x^2y^4\sqrt{3x}$

Because:

$\sqrt{y^8}=\sqrt{(y^4)^2}=y^4$

Therefore: He should have written the square root of $y^8$ in the answer as $y^4$ , not $y^2$ ,

5 0

3 years ago

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