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Mama L [17]
2 years ago
6

Ces

Physics
1 answer:
igomit [66]2 years ago
4 0

Answer:

152 cm

Explanation:

16 hands * 9.5 cm / hand = 152 cm

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Why isn't Coulomb's law valid for dielectric objects, even if they are spherically symmetrical?
marshall27 [118]

Answer:

Explanation:

The "traditional" form of Coulomb's law, explicitly the force between two point charges. To establish a similar relationship, you can use the integral form for a continuous charge distribution and calculate the field strength at a given point.

In the case of moving charges, we are in presence of a current, which generates magnetic effects that in turn exert force on moving charges, therefore, no longer can consider only the electrostatic force.

4 0
3 years ago
A 200-foot tall monument is located in the distance. From a window in a building, a person determines that the angle of elevatio
egoroff_w [7]

Answer:

665 ft

Explanation:

Let d be the distance from the person to the monument. Note that d is perpendicular to the monument and would make 2 triangles with the monuments, 1 up and 1 down.

The side length of the up right-triangle knowing the other side is d and the angle of elevation is 13 degrees is

dtan13^0 = 0.231d

Similarly, the side length of the down right-triangle knowing the other side is d and the angle of depression is 4 degrees

dtan4^0 = 0.07d

Since the 2 sides length above make up the 200 foot monument, their total length is

0.231d + 0.07d = 200

0.301 d = 200

d = 200 / 0.301 = 665 ft

7 0
3 years ago
Find the initial velocity of a ball that has a final velocity of 17.9 m/s, west after it accelerated at 63.7 m/s2, west for 0.21
Musya8 [376]

Explanation:

Taking west to be positive, given:

v = 17.9 m/s

a = 63.7 m/s²

t = 0.21 s

Find: v₀

v = at + v₀

17.9 m/s = (63.7 m/s²) (0.21 s) + v₀

v₀ = 4.52 m/s

The initial velocity is 4.52 m/s west.

5 0
3 years ago
What is atmospheric pressure and what are the diffetent units?
Burka [1]
Atsmopheric pressure is the pressure that is on something inside and atmosphere. measured in either mmhg or milimeters of Mercury, or atmospheres abreviated atm.
6 0
3 years ago
The driver of a 770 kg car decides to double the speed from 23.1 m/s to 46.2 m/s. What effect would this have on the amount of w
Ne4ueva [31]

Answer:

The final kinetic energy is four times of initial kinetic energy when speed of the car doubles.

K_{2} = 4 K_{1}

Explanation:

Mass of the car = 770 kg

initial speed V_{1} = 23.1 \frac{m}{s}

Final speed V_{2} = 46.2 \frac{m}{s}

Initial kinetic energy K_{1} = \frac{1}{2} m V_{1} ^{2}

⇒ K_{1} = 0.5 × 770 × 23.1^{2}

⇒ K_{1} = 205440 J

Final kinetic energy  K_{2} = \frac{1}{2} m V_{2} ^{2}

⇒ K_{2} = 0.5× 770 × 46.2^{2}

⇒ K_{2} = 821760 J

Thus K_{2} = 4 K_{1}

Therefore the final kinetic energy is four times of initial kinetic energy when speed of the car doubles.

5 0
3 years ago
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