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Karo-lina-s [1.5K]
3 years ago
15

A boy and his skateboard have a combined mass of 65 kg what is the speed of the boy and skateboard if they have a momentum of 27

5 kg•m/s
Physics
1 answer:
kvasek [131]3 years ago
3 0
Let m = 65 kg, the mass of the boy and skateboard.
Let v = speed of the boy and skateboard.

The momentum is
P = mv = (65 kg)*(v m/s) = 275 (kg-m)/s²
v = 275/65 = 4.23 m/s

Answer:  4.23 m/s
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Acar accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is
s2008m [1.1K]

To understand this question, you need to understand the concept of acceleration first. Have you ever been in a car and noticed that it was getting faster and faster? That "speeding up" of the car is known as acceleration! Acceleration is essentially the rate at which you speed up.

Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: \frac{∆v}{t}

If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 \frac{feet}{second} then sped up to 5 \frac{feet}{second}, then the change in my speed would be 2 \frac{feet}{second}, because I started walking 2 \frac{feet}{second} faster!

Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 \frac{meters}{second} to 16 \frac{meters}{second}  in 4 seconds. What would the acceleration be? Let's set up an equation:

a = \frac{∆v}{t}

a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.

Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 \frac{meters}{second} by 4 \frac{meters}{second}. That makes sense, right? Back to the equation.

a = \frac{∆v}{t}
a = \frac{16-4}{4}

(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)

a = \frac{12}{4}

a = 3 (\frac{meters}{second^{2}})

We have our answer! The car's acceleration is 3 meters per second^{2}.

(You might be thinking: Wait. Meters per second squared? The reason for that is because acceleration is the rate at which the speed increases! That makes the unit \frac{\frac{meters}{second}}{second}, which can be simplified down to \frac{meters}{second^{2} })

Let me know if you need clarification on anything I explained here!
- breezyツ

6 0
2 years ago
Beginning at the NW corner of the intersection of Pine & 675, thence north 950 feet, thence west 380 feet, thence south 950
Serjik [45]

Answer:

this description is valid for mediadle displacement, bone is an acceptable description

Explanation:

The description of a person's position must be done with a position vector. These vectors must have magnitude, a given direction and a starting point.

In the description this has a starting point corner NO of pine and 675.

Each displacement occurs with respect to the previous one, indicating the magnitude of the displacement and its direction.

After analyzing  this description is valid for mediadle displacement, bone is an acceptable description

6 0
4 years ago
A
dangina [55]

Answer:

C 2000v its obviously ans because if o is 1000 2 vo is 2000v

7 0
2 years ago
How many newtons of force are represented by the following amount: 3 kg·m/sec^2?
Jet001 [13]
1N=1kg•m/s^2 so the answer is 3N
8 0
3 years ago
In 8.4 s a fisherman winds 2.9 m of fishing line onto a reel whose radius is 3.0 cm (assumed to be constant as an approximation)
alukav5142 [94]

Answer:

The angular speed of the reel is 11.33 rad/s

Explanation:

Given

The fisherman takes t = 8.4 s to wind distance x = 2.9 m into a circle radius of r = 3 cm = 0.03 m

Than the tangencial speed equals the change in the distance to the time

v = \frac{x}{t} = \frac{2.9 m}{8.4 s} = 0.34 \frac{m}{s}

Knowing the tangencial velocity is proportional to the radius r and the angular velocity

v = r*w

w = \frac{0.34 m/s}{0.03 m} = 11.33 \frac{rad}{s}

3 0
3 years ago
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