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2 years ago

What is the primary difference between an ideal emf device and a real emf device?.

Physics

2 answers:

Law Incorporation [45]2 years ago

5 0

Answer:

A real emf device will have internal resistance and the ideal emf will not

Hope this Helps!

EleoNora [17]2 years ago

3 0

Answer:

A real emf device has an internal resistance, but an ideal emf device does not.

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A gas cylinder is filled with 4.00 moles of oxygen gas at 300.0 k. the piston is compressed to yield a pressure of 400.0 kpa. wh

Radda [10]

To answer this item, it is assumed that the gas in the cylinder is ideal such that it follows the equation,
PV = nRT
when V is to be calculated,
V = nRT/P
V = (4)(0.0821 L.atm/molK)(300 K) / (400 kPa/101.325 kPa/atm)
V = 24.95 L
Thus, the volume of gas in the cylinder is 24.95 L.

8 0

3 years ago

Let f be the function that determines the area of a circle (in square cm) that has a radius of r cm. That is, f ( r ) represents

emmasim [6.3K]

Answer:

$f(r)=\pi.r^2\\f(4.3)=58.09\ cm^2$

Explanation:

Functions

When one magnitude depends on other (or others), we usually try to express them as a function which can contain any number of variables, constants, and operations.

The area of a circle is computed by the well-known formula

$A=\pi r^2$

We are required to use function notation to express the area of a circle f(r) in terms of the radius r. If the radius is in cm, then the area is in $cm^2$ .

The required function is

$f(r)=\pi r^2$

For a radius of 4.3 cm:

$f(4.3)=\pi\times 4.3^2=58.09\ cm^2$

$\boxed{f(4.3)=58.09\ cm^2}$

4 0

3 years ago

Before a collision, a 50.0-kg object is moving at +5.0 m/s. Find the impulse that acted on the object if, after the collision, i

Virty [35]

Answer:

J=600 kg m/s

Explanation:

Impulse And Momentum

Suppose a particle is moving at a certain speed $v_1$ and changes it to $v_2$ . The impulse J is equivalent to the change of linear momentum. The momentum can be computed by

$p=mv$

The initial and final momentums are given, respectively, by:

$p_1=mv_1,\ p_2=mv_2$

Thus, the change of momentum is

$\Delta p=p_2-p_1=m(v_2-v_1)$

It's equal to the Impulse J

$J=\Delta p$

$J=m(v_2-v_1)$

Our data is

$m=50\ kg,\ v_1=5\ m/s,\ v_2=17\ m/s$

$J=50\ (17-5)$

$J=600\ kg\ m/s$

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3 years ago

The passenger in a moving bus falls forward suddenly explain

Ksju [112]

Answer:

the kinetic energy force made the not to stay in a position if the person is not careful

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3 years ago

What most closley defines population density?

Genrish500 [490]

The carrying capacity of a biological species in an environment is the maximum population size of the species that the environment can sustain indefinitely, given the food, habitat, water, and other necessities available in the environment.

3 0

4 years ago