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Pavel [41]
1 year ago
9

Hi! does anyone know how to solve this problem?

Mathematics
1 answer:
masha68 [24]1 year ago
3 0

Answer:-5

Step-by-step explanation:

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Find the value of x <br> x°<br> 100°<br> 135°
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Answer:

Sqoo= 2 (100 + 999) - 5300 = 3 (100 + 999). Saoo=494,550 ... Find the values of x for which (fºg)(x) <(gºf)(x). f(x) = 2x – 1 g(x) = " x+1'47-1.

4 0
3 years ago
Rosa's monthly mortgage payment was $1400 last year, and on average, 8%
Shkiper50 [21]
A. $112 but am not sure
6 0
3 years ago
The function g(x) is graphed.
sergejj [24]

g(1)=-1 :  We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.

So, g(1)=-1  is false.

g(0)=0 : We need to check values of function for x=0. From the graph, we can see, for x=0 the value of y is 0.

So, g(0) =0 is true.

g(4)=-2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to -2.

So, g(4)=-2 is false.

g(1)=1 :We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.

So, g(1) =1 is true.

g(-1)=1 :We need to check values of function for x=-1. From the graph, we can see, for x=-1 the value of y is 1.

So, g(-1)=1 is true.

g(4)=2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to 2.

So, g(4)=2 is false.

3 0
3 years ago
Can you plz help me with this math problem?
Sedaia [141]

Answer:

B

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
What is the interest rate of each investment if The annual interest on a $17,000 investment exceeds the interest earned on an $8
Butoxors [25]

<u>Solution-</u>

Let's assume, the rate of interest of $8000 is x%,

then the rate of interest of $17000 is (x+0.3x) =1.3x%

Interest earned by $8000,

i_1=\frac{8000\times x\times 1}{100} =80x

Interest earned by $17,000,

i_2=\frac{17000\times 1.3x\times 1}{100} =221x

According to the question,

\Rightarrow i_1=i_2+276

\Rightarrow 221x=80x+276

\Rightarrow 221x-80x=276

\Rightarrow 141x=276

\Rightarrow x=1.96

∴ Rate of interest of $8000 is 1.96% and rate of interest of $17000 is (1.3×1.96) =2.55%

3 0
3 years ago
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