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3241004551 [841]
3 years ago
8

Need help with this 1 math problem.​

Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:ok

Step-by-step explanation:

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Please help asap I'm not sure how much time I have
BlackZzzverrR [31]
Tan 37,4 = opposite/adjacent

tan 37,4 = x/12,8
• then multiply both sides by 12,8

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Therefore x = 9, 79 x 100
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Second one:

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f(x)=\sqrt{x-7}+9\\\\\text{the domain:}\\x-7\geq0\to x\geq7\\\\\text{the range:}\\\sqrt{x-7}\geq0\ \text{therefore}\ \sqrt{x-7}+9\geq9\\\\y\geq9

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Find the volume of the pyramid to the nearest cubic unit. Use a calculator.
Goryan [66]

Answer:

64 m³

Step-by-step explanation:

<u>Formula</u>

\textsf{Volume of a square based pyramid}=\dfrac{1}{3}a^2h

where:

  • a = side length
  • h = perpendicular height

Given:

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  • h = 3 m

Substituting the given values into the formula:

\begin{aligned}\implies \textsf{Volume}& =\dfrac{1}{3} \cdot 8^2 \cdot 3\\\\& = \dfrac{3}{3} \cdot 64\\\\& = 1 \cdot 64\\\\& = 64\:\sf m^3\end{aligned}

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2 years ago
Read 2 more answers
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