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otez555 [7]
1 year ago
12

The area of a rectangle is Aww (1) What is the area of a rectangle that has a width of 34 and a length of 10

Mathematics
1 answer:
sweet-ann [11.9K]1 year ago
8 0
340

Length x width = area
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Please help with these questions and show how u found them i will mark you brainliest
nata0808 [166]

Answer:

5(x+8)

5x+8x

5x+40

6q+2+3q+5

9q+7

8 0
3 years ago
Read 2 more answers
Evaluate the following log32-log64+log16
gogolik [260]
Using properties of logarithms:

log(m+n) = log(m.n)

log(m-n) = log (m/n)

we get,

log(32x16/64)

On simplifying:

log(8)

and 8= 2^3

therefore,

log(2^3)

again using another property for exponents in logarithms we get:

3 log 2 <---- Answer
7 0
3 years ago
Read 2 more answers
Check my answer please? I'll report if you just say yeah and it's not correct lol.
Elena-2011 [213]
Yes, set up your proportion: x/21 = 10/14
Cross multiply 14x = 210
Divide both sides by 14 and x= 15 cm
7 0
3 years ago
Read 2 more answers
PLEASE SOMEBODY HELP MEEEE
andreyandreev [35.5K]
That's an equal to or less then sign so 10 or anything below should be correct
3 0
2 years ago
Read 2 more answers
Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d​
gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

Step-by-step explanation:

Evaluate:

\dfrac{b-3a}{bc^{2}-d}

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\

\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

6 0
3 years ago
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