2 years ago

The area of a rectangle is Aww (1) What is the area of a rectangle that has a width of 34 and a length of 10

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

8 0

340

Length x width = area

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If triangle DEF is an isosceles triangle with DE is congruent to EF, find x and the measure of each side

Rudik [331]

Step-by-step explanation:

Given that,

DE = 8x - 13

EF = 5x + 17

DF = x + 21

Also,

DE = EF

which means that,

8x - 13 = 5x + 17

8x - 5x = 17 + 13

3x = 30

x = 30/3

x = 10

Now,

DE = 8x - 13 = 8×10 - 13 = 80 - 13 = 67cm

EF = 5x + 17 = 5×10 + 17 = 50 + 17 = 67cm

DF = x + 21 = 10 + 21 = 31cm

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A survey of one class at Pioneer Middle School found that 20 out of 30 students would spend $12 for a school t-shirt Suppose the

Virty [35]

$\frac{20}{30} = \frac{x}{600}$
600/30=20.
20*20=400.
Your answer is 400.

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4 years ago

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Jeremy wanted to buy a used car for $4000. He had to pay 8% in sales tax. How much is he paying for the car?

lord [1]

Answer:

he pays 4320 :)

Step-by-step explanation:

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3 years ago

Use the quadratic formula to find the solutions for..<br> y = 2x^2 - 9x + 5.

Yakvenalex [24]

Answer: $x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}$

Step-by-step explanation:

$2x^2-9x+5$

a=2

b=-9

c=5

$x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)} }{2(2)}$

$x=\frac{9\frac{+}{}\sqrt{81-40} }{4}$

$x=\frac{9\frac{+}{}\sqrt{41} }{4}$

$x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}$

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3 years ago

An electrician can wire on average 4.5 houses in a week. How many months will it take her to wire 55 houses if she wires the sam

Brrunno [24]

Just do 4.5 x4.5 and get 20.25 then divide that by 55 and get the answer of 2.7 months. Hope this helps

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3 years ago