Answer:
fvgdnsigdv356b cdhfn .44. jcbyd6.5.4.3.3.2.2.3.4.5.6.6.7.7
Step-by-step explanation:
Answer: the above stated equation is a quadratic equation
Step-by-step explanation:
Given the following equations
y = x^2 + 5x - 3....equation 1
y-x = 2
y = x + 2........equation 2
Let equation 1 equal equation 2
x^2 + 5x -3 = x + 2
Bringing the equation to one side and equating to zero
X^2 +5x - 3 -x -2 = 0
X2 + 5x -x -3 -2 = 0
X^2 + 4x -5
Solving the aquatic equation
(x + 5)(x -1) = 0
X + 5 = 0
X1 = -5
X- 1 = 0
X2 = 1
To prove:
Substitute the values for x1and x2 into the equation x^2 + 4x - 5 = 0
If the boat can travel 45 mph in still water and the current is 10 mph, down stream, or with the current, has the boat moving at 55. Upstream has the boat moving 35 mph. It took t time to go with the current and an hour longer, t + 1, to go against it. Going from point A to B and back to A again means that the trip there was the same distance as the trip back. So d is the same for both upstream and downstream. The equation for upstream is d = 35(t + 1) or d = 35t + 35; the equation for downstream is d = 55t. Since the distances are the same, the transitive property says that so are the rates and times; therefore, we can set those equal to one another. 35t + 35 = 55t. Solve for t. When we find that t = 7/4 (1 3/4 hours), we sub that in to solve for distance. 55(7/4) = 96 1/4 miles.
Answer:
arithmetic
Step-by-step explanation:
I think
Square root function. f(x)= square root x x> or = to 0