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3 years ago

I need help please...

Mathematics

2 answers:

Doss [256]3 years ago

7 0

Answer:

No is your answer

Step-by-step explanation:

Yuliya22 [10]3 years ago

3 0

We can most easily solve this by simply inserting the known values and solving.

This is saying that x=1 and y=3. Lets replace the variables with them to solve.

Our equation is now 5(1)+3 is less than or equal to to -3.

Solve.

5+3

8 is definitely tly NOT less than -3. It is 11 more than it. The answer is no.

Hope this helps!

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Mkey [24]

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Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

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Total number of ways in which 12 picture card is distributed = $\frac{12!}{3! 3! 3! 3!}$

Now,

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So,

Total number of ways of getting 3 picture card and remaining card = $\frac{12!}{3! 3! 3! 3!}$ × $\frac{40!}{10! 10! 10! 10!}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = $\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }$

∴ The probability = $\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13!)^{4} }{ 52! }$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }$

= $\frac{12!}{(3!)^{4} }$ × $\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= $\frac{479,001,600}{(6)^{4} }$ × $\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= 0.0324

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The probability that each player will receive three picture cards = 0.0324

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