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postnew [5]
3 years ago
12

Find the equation of the line that has a slope of 3 and passes through the point (-5,4)

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0
We can use point-slope form (since we have the slope, and 1 ordered pair)

point-slope form is y-y1=m(x-x1)

x=-5
y=4
m=3

y-(4)=3(x-(-5)
IRISSAK [1]3 years ago
5 0
Our point-slope formula is (y- y_{1} )=m(x-x_{1})

m=slope
x_{1} = -5
y_{1} =4

Therefor, when we input our values and simplify, we get...

(y-(4))=3(x-(-5) \\ y-4=3x+15 \\ y=3x+19
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\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)}  \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\  \\ \longrightarrow \sf \: 27 - 15 \\  \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}

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