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3 years ago

Find the equation of the line that has a slope of 3 and passes through the point (-5,4)

2 answers:

7 0

We can use point-slope form (since we have the slope, and 1 ordered pair)

point-slope form is y-y1=m(x-x1)

x=-5
y=4
m=3

y-(4)=3(x-(-5)

IRISSAK [1]3 years ago

5 0

Our point-slope formula is $(y- y_{1} )=m(x-x_{1})$

m=slope
$x_{1} = -5$
$y_{1} =4$

Therefor, when we input our values and simplify, we get...

$(y-(4))=3(x-(-5) \\ y-4=3x+15 \\ y=3x+19$

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Bryan drives at an average speed of 60 miles per hour.

riadik2000 [5.3K]

Answer:

180

Step-by-step explanation:

Multiply 60x3

and you will get 180miles

3 0

3 years ago

Read 2 more answers

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

4 0

3 years ago

12. What percent of 60 is 12? Show your work.

lora16 [44]

12 is 20% of 60 because 12/60 = 0.2.

6 0

3 years ago

Read 2 more answers

The cost of 2 plates of spaghetti & 1 plate of salad is $27.50. The cost for 4 plates of spaghetti & 3 salads is $59.50.

k0ka [10]

2a+1b=27.50

4a+2b=59.50

Multiply first equation by -4 and the second by 2 so you can drop off the a values then add the equations together. Then solve for b. You should get b=6.

Then plug b into one of the original equations and solve for a and you should get 10.75

So a plate of spaghetti is $10.75 and a salad is $6.

<em><u>Please mark brainliest!</u></em>

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3 years ago

Han is in training for a marathon. One day, Han ran 8 miles. The next day, he plans to run that same distance plus half as much

timofeeve [1]

Answer:

hen is in training of Marathon Vande hand run 8 Miles next day he plans to run the same I bless have much so how far does he planned

Step-by-step explanation:

the hendrun 8 and half miles the next radio Follow Me animal lover

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3 years ago