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3 years ago

Find the equation of the line that has a slope of 3 and passes through the point (-5,4)

2 answers:

7 0

We can use point-slope form (since we have the slope, and 1 ordered pair)

point-slope form is y-y1=m(x-x1)

x=-5
y=4
m=3

y-(4)=3(x-(-5)

IRISSAK [1]3 years ago

5 0

Our point-slope formula is $(y- y_{1} )=m(x-x_{1})$

m=slope
$x_{1} = -5$
$y_{1} =4$

Therefor, when we input our values and simplify, we get...

$(y-(4))=3(x-(-5) \\ y-4=3x+15 \\ y=3x+19$

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EXPLANATION

Part a)

The given function is

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$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$

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