Question

consider the equation is Y equals 1/square root of x and y=x-2. approximate solution of the system equations

Answer 1

Answer:

$x=1$ and $x=4$

Step-by-step explanation:

We have the following system of equations:

$y=\sqrt{x}$ and $y=x-2$

To solve the problem, we need to equal the two equations:

$x-2=\sqrt{x}$ ⇒ $(x-2)^{2} =x$ ⇒ $x^{2} -4x + 4 = x$  

⇒ $x^{2} -5x + 4 = 0$  

So you need to find two numbers that added equal to 5 and multiplied equal to 4. These two numbers are $x=-1$ and $x=-4$.

Then, the factorized form of the polynomial is: $(x-1)(x-4)$.

The, the solution to the system of equations is: $x=1$ and $x=4$.