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3 years ago

Given the following linear functions determine the relationship

Mathematics

2 answers:

Dmitrij [34]3 years ago

8 0

Answer:

perpendicular

Step-by-step explanation:

The product of the slopes (5/6), (-6/5) is -1, so the lines described by these functions are perpendicular.

fgiga [73]3 years ago

6 0

Answer: perpendicular

Step-by-step explanation:

Lines with opposite and negated slopes are perpendicular, you can use desmos to graph and check

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I What integer represents 6°F below zero?

NemiM [27]

Answer:

Anything below zero is a negative integer, therefore, the answer would be

-6°F.

~ Hope this helps

3 0

3 years ago

K=am+3mx solve for m

Otrada [13]

Assuming the variables are constants, you isolate m. So move am to the left. K-am=emx. Now divide ex. This gives you, m=(K-am/ex)

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3 years ago

Please answer this correctly

GREYUIT [131]

Answer:

$8.82

Step-by-step explanation:

4.6 (1.15) + 0.5 (1.12) + 2.25 (1.32)

5.29 + 0.56 + 2.97

8.82

8 0

3 years ago

three students had $9.00 total and went to a smack bar where their bill was $6.57. they want to divide up the money that is left

KatRina [158]

9.00+6.57=× is the answer

3 0

2 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the <u>zero-product property</u> and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the <u>second equation</u> and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

6 0

10 months ago

Read 2 more answers