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2 years ago

It takes 0.5 gallon of cream to make 1 pound of butter.

Mathematics

1 answer:

Pavlova-9 [17]2 years ago

4 0

Yes I think it really is the correct answer

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A price is decreased by 24% and is now £372.40.<br>Work out the original price.

goldfiish [28.3K]

Answer:

Step-by-step explanation:

Subtract the discount from 100 to get the percentage of the original price.

Multiply the final price by 100.

Divide by the percentage in Step One

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3 years ago

Which of these numbers is prime? 18, 41, 45, 77, 93

elena-14-01-66 [18.8K]

The answer to your question is 41

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3 years ago

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The table shows the number of books each student read this month. Move bars to the graph to show data.

Airida [17]

This is so easy. The answers are literally right there

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3 years ago

One end of a cable is attached to the top of a flagpole and other end is attached 6 feet away from the base of the pole. If the

kvv77 [185]

Answer:

Step-by-step explanation:

hypotenuse

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3 years ago

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All 6 members of a family work. Their hourly wages (in dollars) are the following.37, 38, 39, 40, 39, 11Assuming that these wage

tiny-mole [99]

We have a sample that in fact represents the population.

We have to calculate the standard deviation of this population.

The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).

We have to start by calculating the mean of the population first:

$\begin{gathered} \mu=\dfrac{1}{n}\sum ^n_{i=1}\, x_i \\ \mu=\dfrac{1}{6}(37+38+39+40+39+11) \\ \mu=\dfrac{204}{6} \\ \mu=34 \end{gathered}$

Now, we can calculate the standard deviation as:

$\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}$ $\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}$

Answer: the standard deviation of this population is approximately 10.33

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2 years ago