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algol13
2 years ago
5

Which expression has the same value as -73 +3/?

Mathematics
1 answer:
vovikov84 [41]2 years ago
4 0

The expression come -70

given;

In mathematics, multiplication can be represented by using the symbol × or the symbol ·. Moreover, multiplication can be also represented just by leaving the numbers or values side by side without any symbol. For example, the expression 5x + y implies 5 should be multiplied by x. In this context, the expression  indicates -73 + 3

it means ; the number 73 substract from 3 and we get - 70.

to know more about mathematical expression;

visit; brainly.com/question/17241535

When we combine numbers and variables in a valid way, using operations such as addition, subtraction, multiplication, division, exponentiation, and other operations and functions as yet unlearned, the resulting combination of mathematical symbols is called a mathematical expression.

#SPJ9

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What is the weight of one half of two thirds of a sack of rice? The sack of rice weighs 99 kilograms.
Eddi Din [679]
First you need to find what 2/3 equals
to do this, take 99 divided by 3
99/3=33

if 1/3 equals 33, two thirds would be 33x2
33x2=66

now, you need to find 1/2 of 66.  this can be done 2 different ways

1.    66 divided by 2    -    66/2=33
OR
2.    66 x 1/2 = 33     OR     66 x .5 = 33

The answer is 33 kilograms

6 0
3 years ago
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For the equation given below, evaluate y′ at the point (−2,2)<br> xe^y−4y=2x−4−2e^2
jeka94
Implicit differentiation
chain rule is important here

I'll show the steps partially
e^y+xe^yy'-4y'=2
xe^yy'-4y'=2-e^y
y'(xe^y-4)=2-e^y
y'=\dfrac{2-e^y}{xe^y-4}
now evaluate for (-2,2)
x=-2 and y=2
y'=\dfrac{2-e^2}{-2e^2-4}
y'=\dfrac{2-e^2}{-2e^2-4}
y'=\dfrac{e^2-2}{2e^2+4}
that's it, simplest form
3 0
3 years ago
Use the functions to answer the question.
Ksivusya [100]
Composition function rule (f○g)(x) = f(g(x))
<em><u /></em><u>Given the separate functions</u>: f(x)=2x+1 and g(x)=x^2

(f\circ g)(-5)\rightarrow\text{ Composition Function Rule}\rightarrow f(g(-5))=2((5)^2)+1
\rightarrow2(25)+1=50+1=51
4 0
3 years ago
Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen
vladimir1956 [14]

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

6 0
3 years ago
Solve the equation by completing the square. If necessary, round to the nearest hundredth.
diamong [38]
Ax^2+bx=c
REMEMBER THIS

ok
first, make sure that a is 1
done

now take 1/2 of b and square it

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square root both sides
don't forget positive and negative root
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ad 9 to both sides

x=19
x=-1




answer is -1; 19

2nd choice is answer
8 0
3 years ago
Read 2 more answers
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