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Lera25 [3.4K]
2 years ago
12

Please help thank you

Mathematics
1 answer:
mars1129 [50]2 years ago
3 0

i have no idea about a but

B. LN corresponds to EF

MN corresponds to DF

E corresponds to L

F corresponds to N

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The area of the trapezoid is 4.5cm
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84

Step-by-step explanation:

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Answer: 11

Step-by-step explanation:

Since the equation of circumference is 2(r)pi

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3 years ago
QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0
3 years ago
What is the value of ?
Ede4ka [16]
Remember
\frac{x^m}{x^n}=x^{m-n}
and
x^{-m}=\frac{1}{x^m}

so
\frac{3^2}{3^4}=3^{2-4}=3^{-2}=\frac{1}{3^2}=\frac{1}{9}
5 0
3 years ago
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