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2 years ago

PLS HELP ITS URGENT ITS DUE TODAY

Biology

2 answers:

Mademuasel [1]2 years ago

5 0

Answer:

oh man, this one can possibly be two correct answers, Either C or D. Can you ask maybe a teacher to help you out? if I had to answer I would probably lean towards D. But I'm not 100% sure. :) Let me know if you get it correct or incorrect :D

Explanation:

Mnenie [13.5K]2 years ago

3 0

C, using a scale to measure the weight of an object

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The number of cells in an average-sized adult human is on the order of 10^14 cells. Use this information, and the estimate that

KengaRu [80]

IF:
Number of cells: $C = 10^{14}$
DNA lenght: $D = 2m = 12.42 * 10^{-4} mi$
Distance from Earth to Sun: $ES=93000000 mi = 9.3* 10^{7}mi$

Then:
a) Over how many miles would the total DNA from the average human stretch?
The answer is product of multiplication of the number of cells (C) and the DNA length (D):
Total DNA: $T = C*D$
⇒ $T = 10^{14}*12.42* 10^{-4} mi$
⇒ $T = 12.42* 10^{14-4} mi$
⇒ $T = 12.42* 10^{10} mi$
The total DNA from the average human will stretch $12.42* 10^{10} mi$

b) How many times would the total DNA from the average human stretch from Earth to the Sun and back?
The answer is concluded from the ratio of the total DNA length (T) and the twice (because of stretch to the Sun and back, thus, two directions) of distance from Earth to the Sun (ES) and :
Ratio: $R= \frac{T}{2*ES}$
⇒ $R = \frac{12.42* 10^{10}mi }{2*(9.3* 10^{7}mi)}$
⇒ $R = \frac{12.42* 10^{10}}{18.6*10^{7}}$
⇒ $R = 0.6677* 10^{10-7}$
 ⇒ $R = 0.6677* 10^{3}$
 ⇒ [tex]R = 667.7
Thus, 667,7 times will the total DNA from the average human stretch from Earth to the Sun and back.

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3 years ago