The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
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Answer:
Step-by-step explanation:
I think it is 22
Answer:
64
Step-by-step explanation:
4^3=64
4*4=16
16*4=64
Divide the figure into 3 shapes
top square
middle trapezoid
bottom rectangle
so
Area of figure
= (10x10) + 1/2(8 + 14)(4) + (20 x 6)
= 100 + 44 + 120
= 264
answer
264 cm^2
2(2d+4)=-3(d+2)
4d+8=-3d-6
4d+3d=-6-8
7d=-14
d=-14/7
d=-2