We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
Answer:
imm didn't understand , what link
Answer:
it is
Step-by-step explanation:
13.8656
Answer: 288/18+7x5
Step-by-step explanation:
D=m-7
d+m=25
m-7+m=25
2m-7=25
2m=32
m=16
d=16-7
d=9
don is 9
