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1 year ago

Multiply 2 2/3 and 1 5/6 Simplify the answer and write as a mixed number.

Mathematics

1 answer:

fiasKO [112]1 year ago

4 0

The answer as a mixed number is 4 8/9

The first step is to write out the fractions and multiply both fractions

2 2/3 × 1 5/6

= 8/3 × 11/6

= 44/9

Convert to a mixed number

= 4 8/9 (as a mixed number)

Hence the mixed number gotten from the simplification is 4 8/9

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What is the factor tree of 8

8090 [49]

THE FACTOR TREE IS : 8=2^3

8 0

3 years ago

Jonathan is rolling to dice and needs to roll and 11 to win the game he is playing what is the probability that Jonathan wins th

hjlf

Answer:

1 / 18

Step-by-step explanation:

In a roll of two dice :

Number of faces on a dice = 6

Total sample space for 2 6-sided dice = (number of faces)^Number of dice = 6^2 = 36

Total possible outcomes = 36

Required outcome = sum of 11

11 = {(5,6) ; (6, 5)}) = 2 possibilities

Probability = required outcome / Total possible outcomes

P(obtaining a sum of 11) = 2 / 36 = 1/18

5 0

2 years ago

For which equation is m = 12 the solution? a. 4m=40 b. m+20=42. c. 4m=48. d. m-4=9

Gelneren [198K]

To solve this question, we just need to insert 12 into the m position of each question and see if the equation holds true.

a. 4m = 40

4(12) = 40

48 = 40

48 obviously does not equal 40, so it is not choice A.

b. m + 20 = 42

12 + 20 = 42

32 = 42

Again, 32 isn't the same as 42, so not choice B either.

c. 4m = 48

4(12) = 48

48 = 48

It looks like this one is true, but let's solve D also just to make sure.

d. m - 4 = 9

12 - 4 = 9

8 = 9

This is false, since 8 does not equal 9.

Therefore, choice C (4m = 48) is the correct answer.
Hope that helped! =)

6 0

2 years ago

Read 2 more answers

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

garri49 [273]

Using the normal distribution and the central limit theorem, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = 0.5$ .

Sample of 100, hence $n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05$

The interval that contains 95.44% of the sample means for male students is between Z = -2 and Z = 2, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$