Please help me with this

Mathematics

1 answer:

swat323 years ago

6 0

Answer:

The answer is 156.25π or about 490.625

Step-by-step explanation:

To find the area of a circle, you use the formula πr² (pi times radius times radius.) The radius is 12.5, so you plug it in to the equation. Once you plug the radius into the equation, you get π times 12.5 times 12.5. This simplifies to 156.25 times pi. If you want to use 3.14 as pi, the final answer is about 490.625. I hope this helps and that you have an fantastic day!!! Hope you stay safe!!!

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Find the length of each segment. SEE EXAMPLES 1 AND 2

wlad13 [49]

The lengths of the line segments are summarized in the following list:

DF = 3
DE = 8 / 3
FG = 3
FH = 9 / 2
GH = 3 / 2
EH = - 11 / 6

<h3>How to calculate the length of a line segment based on point set on a number line</h3>

Herein we have a number line with five points whose locations are known. The length of each line segment is equal to the arithmetical difference of the coordinates of the rightmost point and the leftmost point:

DF = - 1 - (- 4)

DF = 3

DE = (- 1 - 1 / 3) - (- 4)

DE = 3 - 1 / 3

DE = 8 / 3

FG = 2 - (- 1)

FG = 3

FH = (3 + 1 / 2) - (- 1)

FH = 4 + 1 / 2

FH = 9 / 2

GH = (3 + 1 / 2) - 2

GH = 1 + 1 / 2

GH = 3 / 2

EH = (3 + 1 / 2) + (- 1 - 1 / 3)

EH = - 2 + (1 / 2 - 1 / 3)

EH = - 2 + 1 / 6

EH = - 11 / 6

To learn more on lengths: brainly.com/question/8552546

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7 0

2 years ago

A professor has recorded exam grades for 10 students in his class, but one of the grades is no longer readable. If the mean sco

Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

$\frac{R+x}{10} =80$

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

$\frac{R}{9} = 85\\$ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.