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ivann1987 [24]
2 years ago
10

Please help me with this

Mathematics
1 answer:
swat322 years ago
6 0

Answer:

The answer is 156.25π or about 490.625

Step-by-step explanation:

To find the area of a circle, you use the formula πr² (pi times radius times radius.) The radius is 12.5, so you plug it in to the equation. Once you plug the radius into the equation, you get π times 12.5 times 12.5. This simplifies to 156.25 times pi. If you want to use 3.14 as pi, the final answer is about 490.625. I hope this helps and that you have an fantastic day!!! Hope you stay safe!!!

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sukhopar [10]

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Step-by-step explanation:

8 0
2 years ago
What is the slope of the line
STALIN [3.7K]
The answer you chose in the photo is correct !!
5 0
2 years ago
A door has an area of 21 square feet. It is 7 feet tall. How wide is the door?
Sati [7]

Answer:

3 feet wide

Step-by-step explanation:

21/7= 3

8 0
3 years ago
And angle measures 54° more than the measure of its complementary angle what is the measure of each angle
Mashutka [201]
Answer:
The measure of the angles are 72 degrees and 18 degrees
Step-by-step explanation:
we know that
If two angles are complementary, then their sum is equal to 90 degrees
Let
x -----> the measure of an angle
y-----> the measure of he other angle
we know that
x+y=90 -----> y=90-x -----> equation A
x=y+54 ----> equation B
substitute equation B in equation A and solve for y
y=90-(y+54)
y=90-y-54
2y=36
y=18°
Find the value of x
x=y+54 -----> x=18+54=72°
therefore
The measure of the angles are 72 degrees and 18 degrees
4 0
3 years ago
What is the equation process to this question?
Andreyy89

The given equation is h(t)=-16t^2+80t+4 where h is the height, in feet, of a ball and t is the time, in seconds.

<u>Part a: The height of the ball when t = 2 seconds:</u>

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation h(t)=-16t^2+80t+4, we get;

h(2)=-16(2)^2+80(2)+4

Simplifying the terms, we get;

h(2)=-64+160+4

h(2)=100

Thus, the height of the ball after 2 seconds is 100 feet.

<u>Part b: The height of the ball when t = 4 seconds:</u>

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation h(t)=-16t^2+80t+4, we get;

h(4)=-16(4)^2+80(4)+4

Simplifying the terms, we get;

h(4)=-256+320+4

h(4)=68

Thus, the height of the ball after 4 seconds is 68 feet.

5 0
3 years ago
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