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bagirrra123 [75]
1 year ago
14

One year on Venus is equivalent to 224.7 days on Earth. How many days on Earth, in decimal from, are equivalent to 9 ½ years on

Venus?
Mathematics
1 answer:
Ivan1 year ago
6 0

By using simple rule of three, a period of 9.5 years on Venus is equivalent to 2134.65 terrestrial days.

<h3>How many terrestrial days are equivalent time in Venus?</h3>

One year on Earth is equivalent to 365.3 days and one year on Venus is equivalent to 224.7 days, the equivalent terrestrial time of 9.5 years on Venus is found by simple rule of three:

x = 9.5 yr × (224.7 days / 1 yr)

x = 2134.65 days

A period of 9.5 years on Venus is equivalent to 2134.65 terrestrial days.

To learn more on simple rule of three: brainly.com/question/15209325

#SPJ1

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Find the obtuse angle between the following pair of straight lines.
ioda

Given:

y=-2

y=\sqrt{3}x-1

To find:

The obtuse angle between the given pair of straight lines.

Solution:

The slope intercept form of a line is

y=mx+b     ...(i)

where, m is slope and b is y-intercept.

The given equations are

y=0x-2

y=\sqrt{3}x-1

On comparing these equations with (i), we get

m_1=0

m_2=\sqrt{3}

Angle between two lines whose slopes are m_1\text{ and }m_2 is

\tan \theta=\left|\dfrac{m_2-m_1}{1+m_1m_2}\right|

Putting m_1=0 and m_2=\sqrt{3}, we get

\tan \theta=\left|\dfrac{\sqrt{3}-0}{1+(0)(\sqrt{3})}\right|

\tan \theta=\left|\dfrac{\sqrt{3}}{1+0}\right|

\tan \theta=\pm \sqrt{3}

Now,

\tan \theta= \sqrt{3} and \tan \theta=-\sqrt{3}

\tan \theta= \tan 60^\circ and \tan \theta=\tan (180^\circ-60^\circ)

\theta= 60^\circ and \theta=120^\circ

120>90, so it is an obtuse angle and 60, so it is an acute angle.

Therefore, the obtuse angle between the given pair of straight lines is 120°.

6 0
3 years ago
Which of the following ratios is equivalent to 12/15​
Mnenie [13.5K]

4/5 because 12/15 was simplified using 3.

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Which expression is equivalent to -6(3x-2/3)?
Evgesh-ka [11]
Hello!

-6(3x - 2/3)

Distribute the -6

-18x + 4

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Hope this helps!
6 0
2 years ago
2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?
mezya [45]

Answer:

the inverse of the quadratic function f(x) = x^2 - 3  is \mathbf{f^{-1}(x)=\pm \sqrt{x+3}}

Step-by-step explanation:

We need to find inverse of the quadratic function f(x) = x^2 - 3

Let

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x+3=y^2

Taking square root on both sides

\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}

Now replace y with f^{-1}(x)

f^{-1}(x)=\pm \sqrt{x+3}

So, the inverse of the quadratic function f(x) = x^2 - 3  is \mathbf{f^{-1}(x)=\pm \sqrt{x+3}}

3 0
2 years ago
Gabriella and Max worked on their math project for a total of 6 hours. Mx worked on the project for 2 hours by himself. Solve th
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Answer:Gabriella worked 4 hours

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