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adell [148]
3 years ago
8

The range of the function RK) = R +26+1 İS {25, 643. What is the function's domain?

Mathematics
2 answers:
poizon [28]3 years ago
5 0
A I think sorrry if wrong
frozen [14]3 years ago
4 0

Answer:

A

Step-by-step explanation:

hope this helped! please let me know if im wrong

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In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
Find the product ( 1 1+1 ) ( 2 2+1 ) ( 3 3+1 )….. ( +1 ) for k=6
Sedaia [141]
34=97+29=195 and this is your answer
6 0
3 years ago
F(t) = t-1<br> g(t)= t^3 + 4t<br> Find (f -g)(t)
Annette [7]

Answer:

Step-by-step explanation:

t - 1 - t^3 - 4t

-t^3 - 3t

5 0
3 years ago
i need help with questions 12-15. you can choose one but if you can give me all the answers i will mark you brainliest
8090 [49]

For lines to be parallel, the slopes have to be the SAME.

For lines to be perpendicular, the slopes have to be the exact opposite. (opposite sign and number)

For example(perpendicular):

slope is 2

the perpendicular slope is -1/2

slope is -4/5

the perpendicular slope is 5/4


12. line a and b are perpendicular


13. Line a: y = 3/5x + 1

Line b: y = 3/5x - 2/5

Line c: y = 4/6 + 5/3x

line a and b are parallel


14. Line a: y = 3x + 6

Line b: y = 6 - 3x

Line c: y = 2/3x + 6

Neither, none of them are parallel or perpendicular


15. Line a: y = -2/3 + 4/3x

Line b: y = -1/4 - 3/4x

Line c: y = 5 + 3/4x

line a and b are perpendicular

6 0
3 years ago
Yo can someone help me with this? (Links = report)
Troyanec [42]

Answer:

2

Step-by-step explanation:

12.6 divided by pi= 4.01

sqaure root of 4 is 2

7 0
2 years ago
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