<u>Complete Question:</u>
Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.
<u>Correct Answer:</u>
A) 
B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch
<u>Step-by-step explanation:</u>
a. Write an equation to represent the area of the reduced image.
Let the reduced dimensions is by x , So the new dimensions are

According to question , Area of new image is :
⇒ 
⇒ 
⇒ 
So the equation will be :
⇒ 
b. Find the dimensions of the reduced image
Let's solve : 
⇒ 
⇒ 
⇒ 
By Quadratic formula :
⇒ 
⇒ 
⇒ 
⇒
x = 15 is rejected ! as 15 > 10 ! Side can't be negative
⇒ 
Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch
62,900
21,000
126,300
856,700
The answer is: " x < -3 " .
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Explanation:
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Given:
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" 9(2x + 1) < 9x – 18 " ;
First , factor out a "9" in the expression on the right-hand side of the inequality:
9x – 18 = 9(x – 2) ;
and rewrite the inequality:
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9(2x + 1) < 9(x – 2) ;
Now, divide EACH SIDE of the inequality by "9" ;
[9(2x + 1)] / 9 < [9(x – 2)] / 9 ;
to get:
2x + 1 < x – 2 ;
Now, subtract "x" and add "2" to each side of the inequality:
2x + 1 – x + 2 < x – 2 – x + 2 ;
to get:
x + 3 < 0 ;
Subtract "3" from EACH SIDE ;
x + 3 – 3 < 0 – 3 ;
to get:
" x < -3 " .
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Answer:
7
Step-by-step explanation:
This a special 90° 45° 45° triangle and is an Isosceles triangle at the same time
Of one of the equal side is 7 than the other one too must be 7