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navik [9.2K]
3 years ago
15

Help will give brainiest and 20 points, please answer thoroughly and explain ur steps. If you don’t answer properly I will repor

t. The data is shown above, here is the question:
What types of graph could be used to display the data? Explain why u would use it

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Step-by-step explanation:

maybe that is the data where those born in that year are placed

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2. If a gambler makes repeated wagers, each with a probability of winning equal to 0.40, what is
Umnica [9.8K]

The probability of losing first 5 wagers is (0.6)⁵

<u>Explanation:</u>

The probability of winning = 0.4

The probability of losing = 1 - 0.4

                                      = 0.6

Probability of losing their first 5 wagers = ?

Probability of losing first 5 wagers = (0.6)⁵

Therefore, the probability of losing first 5 wagers is (0.6)⁵

3 0
3 years ago
Read 2 more answers
Need help with this question please <br> (1/5 x 5) to the 5th power =
DaniilM [7]

Answer:

1

Step-by-step explanation:

According to the rule of PEMDAS, we must perform parentheses before exponents.

1/5 x 5 = 1

1 to the power of anything is still 1, so that is the answer.

5 0
3 years ago
if 4/3 liters of water are enough to water 2/5 of the plants in the house, howuch water is necessary to water all the plants in
skelet666 [1.2K]

Answer:

Amount = \frac{10}{3}L

Step-by-step explanation:

Given

Water = \frac{4}{3}L

Plants = \frac{2}{5}

Required

Amount of water for the whole plants

The amount of water for the whole plants is calculated as:

Amount = \frac{Water}{Plants}

This gives:

Amount = \frac{4}{3}L/\frac{2}{5} --- The division equation

Convert division to multiplication

Amount = \frac{4}{3}L*\frac{5}{2} --- The multiplication equation

Solving further:

Amount = \frac{4*5}{3*2}L

Amount = \frac{20}{6}L

Simplify:

Amount = \frac{10}{3}L

7 0
3 years ago
Suppose we purchase a larger bag of Skittles. Assume that this size bag always has 100 candies. In this particular bag 30 are gr
Mademuasel [1]

Answer:

Yes, this is surprising. Random samples with this much error are unusual.

Step-by-step explanation:

The expected proportion of green candies in the bag is p=0.20.

We have a sample with proportion p=0.3.

The amount of candies in the bag are 100.

We can calculate the probabilities of having 30 candies out of a sample of size n=100, if the proportion of the population is p=0.2.

This can be modeled by a binomial distribution with these parameters:

\mu=np=100*0.2=20\\\\\sigma=\sqrt{npq}=\sqrt{100*0.2*0.8}=\sqrt{16}=4

Then, the probability of having 30 or more candy in the bag is (applying the continuity factor):

z=(X-\mu)/\sigma=(29.5-20)/4=9.5/4=2.375\\\\\\P(X>30)=P(z>2.375)=0.00877\approx 0.01

There is too little probability (1%) of having 30 green candies in the bag.

8 0
3 years ago
Help me answer these, please<br>(-6)×(-2)= <br>4×(-8)=<br>7×(-5)=​
nikdorinn [45]
2 negatives make a positive.
1 negative and 1 positive make a negative.
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8 0
4 years ago
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