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navik [9.2K]
3 years ago
15

Help will give brainiest and 20 points, please answer thoroughly and explain ur steps. If you don’t answer properly I will repor

t. The data is shown above, here is the question:
What types of graph could be used to display the data? Explain why u would use it

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Step-by-step explanation:

maybe that is the data where those born in that year are placed

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take a better photo this is blurry

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8 0
2 years ago
A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.
TEA [102]

Answer:

(a) Null Hypothesis, H_0 : \mu = $1,150  

    Alternate Hypothesis, H_A : \mu \neq $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

<u><em>Let </em></u>\mu<u><em> = mean of all account balances</em></u>

(a)So, Null Hypothesis, H_0 : \mu = $1,150     {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, H_A : \mu \neq $1,150    {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                               T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average balance = $1,200

             s = sample standard deviation = $126

             n = sample of account balances = 81

(b) So, <u>test statistics</u>  =  \frac{1,200-1,150}{\frac{126}{\sqrt{81} } }  ~ t_8_0

                               =  3.571

The value of the sample test statistics is 3.571.

(c) <u>Now, P-value of the test statistics is given by the following formula;</u>

          P-value = P( t_8_0 > 3.571) = <u>Less than 0.05%</u>

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0
3 years ago
Find <br><img src="https://tex.z-dn.net/?f=%28%20%7B4x%7D%5E%7B2%7D%20%20%2B%203x%29%20%2B%20%28%20%7B7x%7D%5E%7B2%7D%20%20-%205
marishachu [46]

Answer:

11x^2-2x-6

Step-by-step explanation:

(4x^2+3x)+(7x^2-5x-6)= \\\\(4x^2+7x^2)+(3x-5x)-6= \\\\11x^2-2x-6

Hope this helps!

4 0
3 years ago
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