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3 years ago

Pls help I'll give brainliest !!

Mathematics

2 answers:

Mandarinka [93]3 years ago

5 0

Answer:

Step-by-step explanation:

18+18+6+6=48

posledela3 years ago

4 0

Answer:

38 in

Step-by-step explanation:

P=w+w+h+h=18+18+6+6=26+12=38 in

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Papessa [141]

Answer:

i dont get the question

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve the equation, keeping the value for x as an improper fraction. 23x = − 12x + 5 1.Isolate the variable by adding 12x to bot

kogti [31]

Answer:

$x=\frac{30}{7}$

Step-by-step explanation:

We have been given an equation $\frac{2}{3}x=-\frac{1}{2}x+5$ . We are asked to solve our given equation.

First of all, we will add $\frac{1}{2}x$ on both sides of equation to separate x variable on one side of equation.

$\frac{2}{3}x+\frac{1}{2}x=-\frac{1}{2}x+\frac{1}{2}x+5$

$\frac{2}{3}x+\frac{1}{2}x=5$

Now, we will make a common denominator.

$\frac{2*2}{3*2}x+\frac{1*3}{2*3}x=5$

$\frac{4}{6}x+\frac{3}{6}x=5$

Add numerators:

$\frac{4+3}{6}x=5$

$\frac{7}{6}x=5$

Upon multiply both sides of our equation by $\frac{6}{7}$ , we will get:

$\frac{6}{7}*\frac{7}{6}x=5*\frac{6}{7}$

$x=\frac{5*6}{7}$

$x=\frac{30}{7}$

Therefore, the solution for our given equation is $x=\frac{30}{7}$ .

5 0

3 years ago

Read 2 more answers

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that $p = 0.95$

10 targets

This means that $n = 10$

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

$P(X = 10) + P(X < 10) = 1$

We want P(X < 10). So

$P(X < 10) = 1 - P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987$

$P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401$

40.1% probability that he will miss at least one of them

7 0

2 years ago

Can someone give me the answers for the number frame and how you did it, I’m confused :)

xxTIMURxx [149]

Answer:

16, 56, ...

Step-by-step explanation:

It looks like you have to put in each cell the multiplication of the row and the column, so the columns are 2, 7, 4 etc., and the row is always 8.

First cell: 2x8 = 16

Second cell: 7x8 = 56

and so on

It teaches you to apply the multiplication in a random sequence; you should be able to do this in your head.

8 0

3 years ago

An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con

natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

$L = 3w --- (1)volume = l \times w \times h \\ \\ 88 = (3w) \times w \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\$

The construction cost now is:

$C = 4(l \times w) + 2 ( w \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}$

Now, to determine the minimum cost:

$\dfrac{dC}{dw}= 0 \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}$

$w = \dfrac{88}{3(3)}^{1/3} \ feet$

Now;

$length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet$

$height = ( 88})^{1/3} (3)^{1/3} \ feet$

6 0

3 years ago

Pls help I'll give brainliest !!​

Pls help I'll give brainliest !!