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3 years ago

Which of the following is the correct name for the compound HF

Mathematics

2 answers:

kumpel [21]3 years ago

7 0

Answer:

Los pasajeros pasan por el ____.

equipaje

maletero

control de seguridad

mostrador

Step-by-step explanation:

alexira [117]3 years ago

6 0

Answer: Hydrogen fluoride

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Describe the continuity of the graphed function

marusya05 [52]

we know that

Any function f(x) is continuous at x=a only if

$\lim_{x \to a-} f(x) = \lim_{x \to a+} f(x)=f(a)$

We can see that this curve is smooth everywhere except at x=3

so, we will check continuity at x=3

Left limit is:

$\lim_{x \to 3-} f(x) = -\infty$

Right limit is:

$\lim_{x \to 3+} f(x) = +\infty$

Functional value:

$f(3)= DNE$

we can see that left limit is not equal to right limit

so, limit does not not exist

so, this function is discontinuous at x=3

Since, limit does not exist

so, there will be non-removal discontinuity at x=3

so, option-C........Answer

5 0

2 years ago

Kelsey has saved 35dollars towards the cost of a 390 dollar video game system. In the weeks to come, she plans to save an additi

jeyben [28]

She need 35.5 week to buy this video games system

4 0

3 years ago

Read 2 more answers

Which statement is true? A.27/19<11/30 B.17/31>19/14 C.16/26>30/31 D.35/30<22/12

Mrac [35]

A. $\frac{27}{19}$

To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)

So, solving A, we get 810<209 ... This is false

B. $\frac{17}{31}>\frac{19}{14}$

= 238>589 ..... This is false

C. $\frac{16}{26}>\frac{30}{31}$

= 496>780 .... This is false

D. $\frac{35}{30}$

= 420<660 ..... This is true

Hence, option D is true.

6 0

3 years ago

Find c, if a = 6.5 ft and b = 2.1 ft. Round to the nearest hundredth

daser333 [38]

Answer:

860

Step-by-step explanation:

Eight hundred and sixty.

5 0

3 years ago

Given H(6,7) and I (-7,-6) if point G lies 1/2 of the way long line segment HI, Santiago argues that point G is located at the o

amid [387]

A point that is half way of line segment is the midpoint

Let (6, 7) be (x₁, y₁) and (-7, -6) be (x₂, y₂)

Mid point of HI = ( $\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}$ )
Mid point of HI = ( $\frac{6+-7}{2}, \frac{7+-6}{0})$
Mid point of HI = ( $- \frac{1}{2} , \frac{1}{2}$ )

Santiago's statement is not correct

4 0

2 years ago