3 years ago

Which binomial is a difference of squares?

Mathematics

1 answer:

GenaCL600 [577]3 years ago

7 0

D) 36x^2-81
both 36x^2 and -81 are perfect squares
difference means subtraction

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What is the value of Enter your answer in the box.

Katen [24]

Answer:

x=40

Step-by-step explanation:

The sum of the angles of a triangle add to 180

x+102+38 = 180

Combine like terms

x + 140 = 180

Subtract 140 from each side

x+140-140 = 180-140

x = 40

5 0

3 years ago

I need help with this question it's really important for a important grade pls help if can.

murzikaleks [220]

Answer:

Check pdf

Step-by-step explanation:

Download pdf

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3 years ago

Ill mark brainlist plsshelp

Mars2501 [29]

Multiply both sides by 30
30(15/18) = y
we then multiply 30*15 = 450
450/18 = y
we then get
y = 25

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3 years ago

The ticket booth at a school play sells 216 adult tickets and 162 student tickets. Find the ratio of adults to students. Write y

Svetllana [295]

162:216 -15 =159 witch will be equivalent to your awnser

5 0

3 years ago

A study was done to compare people's religion with how many days that they have said they have been calm in the past three days.

nadezda [96]

Answer:

The probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

Step-by-step explanation:

Represent the provided data as follows:

Compute the probability of the number of Protestants that were calm for 2 out of 3 days as follows:

$P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}$

The number of Protestants surveyed is, n (Protestants) = 99.

The number of Protestants who were calm for 2 days,

n (Protestants who were calm for 2 days) = 6

The required probability is:

$P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}\\=\frac{6}{99}\\ =0.060606\\\approx0.061$

Thus, the probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

3 0

3 years ago