Question

In acidic solution, the breakdown of sucrose into glucose and fructose has this rate law: Rate = k[H⁺][sucrose]. The initial rate of sucrose breakdown is measured in a solution that is 0.01 M H⁺, 1.0 M sucrose, 0.1 M fructose, and 0.1 M glucose. How does the rate change if(c) [H⁺] is changed to 0.0001 M?

Answer 1

The rate change if(c) [H⁺] is changed to 0.0001 M is 0.01.

What is an acidic solution?

A solution with a pH lower than 7 is said to be acidic. Acidic solutions have pH values lower than 7. Fructose is created when glucose is broken down.

Sucrose + H+ =  fructose + glucose

The rate law of reaction is R = k [H+] [sucorse]

H+ = 0.01 M

[sucrose] = 1.0 M

A solution with the following ingredients is used to measure the starting rate of sucrose breakdown: 0.01 M H+, 1.0 M sucrose, 0.1 M fructose, and 0.1 M glucose.

The rate of the reaction when  is changed to 0.001 M = R'

R = k [0.0001M] [1.0 M]

2 / 1

$\dfrac{R'}{R} = \dfrac{ [0.0001M] [0.1M]}{ k [0.1M] [0.1M]}$

R' = 0.01 x R

Thus, the rate change is [H⁺] is changed to 0.0001 M is 0.01.

To learn more about the acidic solutions, refer to the below link:

brainly.com/question/13655896

#SPJ4